The ability of lizards to recognize their predators via tongue flicks can often mean life or death for lizards. Seventeen juvenile commonlizards were exposed to the chemical cues of the viper snake. Their responses, in number of tongue flicks per 20 minutes, are presented below.557, 200, 353, 472, 438, 693, 268, 336, 744, 795,540, 727, 676, 336, 217, 370, 523a) Preliminary data analyses indicate that you can reasonably apply the z-interval procedure.. Find a 90% confidence interval for the meannumber of tongue flicks per 20 minutes for all juvenile common lizards.. Assume a population standard deviation of 190.0. Note: The sum of thedata is 8245.Give your answers to at least 2 decimal places.Confidence interval: (b) Which of the following is the correct interpretation for your answer in part (a)?OA. We can be 90% confident that the mean number of tongue flicks per 20 minutes for this sample of 17 lizards lies in the intervalB. There is a 90% chance that the mean number of tongue flicks per 20 minutes for all juvenile common lizards lies in the intervalOC. We can be 90% confident that the mean number of tongue flicks per 20 minutes for all juvenile common lizards lies in the intervalOD. None of the above

Answered: Image /qna-images/answer/a2f9cf24-0cba-4f69-812d-02a0db00f850.jpg

Answered: The ability of lizards to recognize…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the missing values marked xx and yy in the following contingency table. Age Group Preferred Form of Exercise Total Running Biking Swimming Under 35 years 149 136 yy 364 35 years or older 48 xx 38 141 Total 197 191 117 505 A. xx = 55, yy = 79 B. xx = 103, yy = 77 C. xx = 103, yy = 79 D. xx = 55, yy = 77
25.) 90% of all dogs have city licenses. If 7020 licenses have been issued, how many dogs are there in the city? 25.)
A survey of people who attended the Mombasa New Year celebrations at Mombasa villageyielded the following results:120 were women150 spoke Swahili170 were married108 of the men spoke Swahili100 of the men were not married18 of the non-Swahili-speaking women were married78 non-Swahili-speaking men were not married30 of the women who spoke Swahili were marriedRequired(i) Represent this information on a Venn diagram.(ii) How many people attended?(iii) How many of those who attended did not speak Swahili?(iv) How many women were not married?(v) How many of those who were married were Swahili-speaking men?
8. The numbers of ant nests in each tree from a random sample of palm trees is summarized in the frequency table below: Number of nests 5 6 7 8 10 11 12 13 Frequency 1 2 1 2 2 6. 3 2 a. Calculate the sample size of the sample summarized by the frequency table. b. How many trees in the sample had exactly 6 ant nests? С. How many trees in the sample had at least 11 ant nests? d. Calculate the mode of this sample. е. Calculate the mean of this sample. Use two decimal place accuracy. f. Calculate the five-number summary of this sample; that is, calculate the minimum, first quartile, median, third quartile and maximum of this sample.
During an international conference of journalists, 250 journalists from different countries attended the said event. It was noticed that journalists are multilingual - they can speak 2 or more lsngusges. Based on the information given below: 1. 77 journalists can speak French 2. 120 journalists can speak English 3. 102 journalist can speak German 4. 25 can speak both english and french 5. 30 can speak both english and german 6. 22 can speak both french and german Use venn-diagram to find the answer to the following questions: a. what is the minimum number of journalists that can speak all the three languages? b. some journalists came from south korea and japan and they could only speak their own native language(either japanese or korean), what is the total number of journalists that can speak either korean or japanese?
Find the five-number summary of the scores in the Math 130 test pre-sented in Table 4.1, page 112. Draw the boxplot.
There is some evidence that drinking moderate amounts of wine helps prevent heart attacks. following data on yearly wine consumption (liters of alcohol from drinking wine, per person) and yearly deaths from heart disease (deaths per 100,000 people) were collected the early 1990’s from 19 nations: Alcohol from wine Heart disease deaths Alcohol Country Heart discase deaths Country from wine Australia Austria Belgium Canada Denmark Finland France Iceland Ireland Italy Netherlands New Zealand Norway Spain Sweden Switzerland United Kingdom United States West Germany 167 266 227 2.5 18 211 167 131 191 220 297 71 211 300 107 1.9 0.8 65 1.6 3.9 2.9 2.4 2.9 0.8 86 207 5.8 1.3 1.2 2.7 115 285 199 172 9.1 0.8 0.7 7.9 Summary information: Alcohol from wine Heart disease deaths Мean 3.03 191.05 Standard Deviation 2.51 68.40 r = 0.71 Pleases, answer the following questions: 1- Explain what the value of r² = 0.71 represents in this study?
Find the mode of the following number of states randomly selected travelers at a service plaza visited in the past three years. 18,13,8,8,13,10,13,10,9,18.
Listed below are the numbers of words spoken in a day by each member of eight different randomly selected couples. Complete parts (a) and (b) below. 1395 8071 Male 16,157 25,829 18,389 15,835 14,536 26,744 O Female 24,483 13,192 18,156 17,633 12,556 16,421 15,826 18,164 a. Use a 0.01 significance level to test the claim that among couples, males speak fewer words in a day than females. In this example, p is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the words spoken by the male minus words spoken by the female. What are the null and alternative hypotheses for the hypothesis test? Ho: He word(s) word(s) H₁: Pd (Type integers or decimals. Do not round.) Identify the test statistic. t=(Round to two decimal places as needed.) Identify the P-value. P-value= (Round to three decimal places as need ▸ What is the conclusion based on the hypothesis test? Since the P-value is the significance level, the null…
The ability of lizards to recognize their predators via tongue flicks can often mean life or death for lizards. Seventeen juvenile common lizards were exposed to the chemical cues of the viper snake. Their responses, in number of tongue flicks per 20 minutes, are presented below. 319, 676, 710, 455, 744, 200, 370, 200, 472, 336, 455, 642, 795, 795, 438, 540, 489 Assuming normal distribution, a) Find a 90% confidence interval for the mean number of tongue flicks per 20 minutes for all juvenile common lizards. Assume a population standard deviation of 190.0. Note: The sum of the data is 8636. Confidence interval: (, ). b) Which of the following is the correct interpretation for your answer in part (a)? A. We can be 90% confident that the mean number of tongue flicks per 20 minutes for this sample of 17 lizards lies in the interval B. There is a 90% chance that the mean number of tongue flicks per 20 minutes for all juvenile common lizards lies in the interval C. We can be 90% confident…

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