The 83-lb crate is carefully placed with zero velocity on the incline. What is the acceleration of the block (positive down the incline) if (a) e = 13° and (b) e = 23°? H, = 0.35| H = 0.30 83 lb Answers: (a) 0 - 13°, а- ft/sec2 (Б) Ө - 23°, а - ft/sec2
The 83-lb crate is carefully placed with zero velocity on the incline. What is the acceleration of the block (positive down the incline) if (a) e = 13° and (b) e = 23°? H, = 0.35| H = 0.30 83 lb Answers: (a) 0 - 13°, а- ft/sec2 (Б) Ө - 23°, а - ft/sec2
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter6: Beams And Cables
Section: Chapter Questions
Problem 6.78P: The chain OA is 25 ft long and weighs 5 lb/ft. Find the maximum force in the chain and the distance...
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![The 83-lb crate is carefully placed with zero velocity on the incline. What is the acceleration of the block (positive down the incline) if
(a) e = 13° and (b) e = 23°?
u, = 0.35)
83 lb
He = 0.30
Answers:
(a) e = 13°,
i
ft/sec2
a =
(b) e = 23°, a =
ft/sec2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5538ea3-691d-40fb-afcf-0190a2b87347%2F182199a4-59e2-40fa-aafd-308f1c45bca2%2F1nplall_processed.png&w=3840&q=75)
Transcribed Image Text:The 83-lb crate is carefully placed with zero velocity on the incline. What is the acceleration of the block (positive down the incline) if
(a) e = 13° and (b) e = 23°?
u, = 0.35)
83 lb
He = 0.30
Answers:
(a) e = 13°,
i
ft/sec2
a =
(b) e = 23°, a =
ft/sec2
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