**Explanation of Work Done by Friction on a Sliding Crate****Problem Statement:**A 61-lb crate slides down a curved path in the vertical plane. The crate begins with a velocity of 6.8 ft/sec down the incline at point A and reaches a velocity of 23.5 ft/sec at point B. We need to compute the work \( U_f \) done on the crate by friction during its motion from point A to point B.**Graphical Explanation:**In the accompanying diagram:- Point A marks the starting position at the top of the incline.- Point B marks the ending position at the bottom of the incline.- There is a curve between points A and B representing the path of the crate.- The initial velocity at A is 6.8 ft/sec, indicated by an arrow pointing down the incline.- The final velocity at B is 23.5 ft/sec, illustrated by an arrow pointing right.- The vertical height from A to the ground level is 16 feet.- The horizontal distance from the vertical line at A to B is 25 feet.**Calculation Submission:**Upon inputting the answer for the work done by friction \( U_f \), the calculated value provided was 435 ft-lb. However, it appears that this solution is marked as "Incorrect."It is important for students to ensure they review their calculations considering all forces acting on the crate, including gravitational force and friction, and potentially use energy conservation principles to obtain the correct work done by friction.This problem is commonly encountered in physics and engineering courses and provides practical application of kinematic equations and energy principles.(Note: "ft-lb" signifies foot-pound, a unit of work or energy in the Imperial system.)

Answered: Image /qna-images/answer/34fcce88-e9dd-49c8-ac02-bbf3174c8ab6.jpg

The 61-lb crate slides down the curved path in the vertical plane. If the crate has a velocity of 6.8 ft/sec down the incline at A and a velocity of 23.5 ft/sec at B, compute the work Uf done on the crate by friction during the motion from A to B.

The 61-lb crate slides down the curved path in the vertical plane. If the crate has a velocity of 6.8 ft/sec down the incline at A and a velocity of 23.5 ft/sec at B, compute the work Uf done on the crate by friction during the motion from A to B.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Conservation of Energy

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Question

**Explanation of Work Done by Friction on a Sliding Crate**

**Problem Statement:**
A 61-lb crate slides down a curved path in the vertical plane. The crate begins with a velocity of 6.8 ft/sec down the incline at point A and reaches a velocity of 23.5 ft/sec at point B. We need to compute the work \( U_f \) done on the crate by friction during its motion from point A to point B.

**Graphical Explanation:**
In the accompanying diagram:
- Point A marks the starting position at the top of the incline.
- Point B marks the ending position at the bottom of the incline.
- There is a curve between points A and B representing the path of the crate.
- The initial velocity at A is 6.8 ft/sec, indicated by an arrow pointing down the incline.
- The final velocity at B is 23.5 ft/sec, illustrated by an arrow pointing right.
- The vertical height from A to the ground level is 16 feet.
- The horizontal distance from the vertical line at A to B is 25 feet.

**Calculation Submission:**
Upon inputting the answer for the work done by friction \( U_f \), the calculated value provided was 435 ft-lb. However, it appears that this solution is marked as "Incorrect."

It is important for students to ensure they review their calculations considering all forces acting on the crate, including gravitational force and friction, and potentially use energy conservation principles to obtain the correct work done by friction.

This problem is commonly encountered in physics and engineering courses and provides practical application of kinematic equations and energy principles.

(Note: "ft-lb" signifies foot-pound, a unit of work or energy in the Imperial system.)

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