A 180-lb snowboarder has speed v = 18 ft/sec when in the position shown on the halfpipe. Determine the normal force on his snowboard and the magnitude of his total acceleration at the instant depicted. Use a value HK = 0.07 for the coefficient of kinetic friction between the snowboard and the surface. Neglect the weight of the snowboard and assume that the mass center G of the snowboarder is 2.2 feet from the surface of the snow. 40° G Answers N = a = V 22' lb ft/sec²

A 180-lb snowboarder has speed v = 18 ft/sec when in the position shown on the halfpipe. Determine the normal force on his snowboard and the magnitude of his total acceleration at the instant depicted. Use a value HK = 0.07 for the coefficient of kinetic friction between the snowboard and the surface. Neglect the weight of the snowboard and assume that the mass center G of the snowboarder is 2.2 feet from the surface of the snow. 40° G Answers N = a = V 22' lb ft/sec²

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

**Problem Statement:**

A 180-lb snowboarder has speed \( v = 18 \) ft/sec when in the position shown on the halfpipe. Determine the normal force on his snowboard and the magnitude of his total acceleration at the instant depicted. Use a value \( \mu_k = 0.07 \) for the coefficient of kinetic friction between the snowboard and the surface. Neglect the weight of the snowboard and assume that the mass center \( G \) of the snowboarder is 2.2 feet from the surface of the snow.

**Diagram Description:**
- The diagram illustrates a snowboarder located on a halfpipe.
- The angle at the snowboarder's position is \(\theta = 40^\circ\).
- The mass center \( G \) of the snowboarder is marked on the figure, which is 2.2 feet above the surface of the halfpipe.
- The snowboarder is moving with a velocity \( v \).

**Answers:**

\( N = \) [Answer in lb - Normal force]

\( a = \) [Answer in ft/sec\(^2\) - Total acceleration]

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