**Analyzing Torque on a Rotating Bar**The diagram illustrates a 4.0-meter-long bar fixed at one end, denoted as point O, allowing it to rotate freely around that point. Three forces are applied to this bar at specific positions and angles, and the task is to determine which of these forces creates zero torque on the bar.### Force and Position Details:1. **16 N Force**: - Magnitude: 16 Newtons (N) - Position: 3.0 meters from point O - Angle of application: 30° above the horizontal, directed towards the left.2. **27 N Force**: - Magnitude: 27 Newtons (N) - Position: 4.0 meters from point O - Angle of application: 90° to the bar, directed upwards.3. **33 N Force**: - Magnitude: 33 Newtons (N) - Position: 0 meters (applied right at O) - Angle of application: 45° below the horizontal, directed towards the right.### Explanation of Forces in Relation to Torque:Each force's contribution to torque (\(\tau\)) depends on the force magnitude (F), the distance from the pivot point (r), and the angle (\(\theta\)) at which the force is applied relative to the bar.\[ \tau = F \times r \times \sin(\theta) \]### Determining Zero Torque:- **The 33 N force**: Since it's applied at the pivot point O (distance r = 0), it creates zero torque regardless of the force magnitude or angle.- **The 16 N force**: \[ \tau_{16N} = 16N \times 3.0m \times \sin(30°) \]\[ \tau_{16N} = 16N \times 3.0m \times 0.5 \]\[ \tau_{16N} \neq 0 \] This force does not generate zero torque because of the non-zero perpendicular distance and angle.- **The 27 N force**:\[ \tau_{27N} = 27N \times 4.0m \times \sin(90°) \]\[ \tau_{27N} = 27N \times 4.0m \times 1 \]

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The 4.0 m long bar shown in the figure is fixed so that it can rotate freely around point O at the end of the bar. Three forces are applied along the bar at the positions and angles shown. Use the convention that a counter-clockwise spin is positive. Which of the following forces creates zero torque on the bar? Mark all that apply. 27 N 16 N 30 +3.0 m→ 45° - 4.0 m- 33 N The 33 N force The 16 N force The 27 N force None

The 4.0 m long bar shown in the figure is fixed so that it can rotate freely around point O at the end of the bar. Three forces are applied along the bar at the positions and angles shown. Use the convention that a counter-clockwise spin is positive. Which of the following forces creates zero torque on the bar? Mark all that apply. 27 N 16 N 30 +3.0 m→ 45° - 4.0 m- 33 N The 33 N force The 16 N force The 27 N force None

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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