The 300-kg mine car is hoisted up a 20° incline using the cable and motor M. For a short time, the force in the cable is F= (400t+1900) N, where t is in seconds. If the car starts from rest at t = 0, find its velocity when t = 3s 9.81 m/s2 = 32.2 ft/s² v=? @t=3s 20⁰
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