NOTE: the friction component is .48ReviewThe 25-lb slender rod has a length of 6 ft Using a collarof nogligible mass, its end A is confined to move alongthe smooth circular bar of radius 3/2 ft End B rests onthe floor, for which the coetficient of kinetic friction isHH =0.48 The bar is released from rest when @- 30(Figure 1)Part ADetermine the angular acceleration of the bar at this instant, measured dockwineExpress your answer using three significant figures. Enter positive value if the angularacceleration is clockwise and negative value if the angular acceleration is counterciockwise.Figure1 of 1>Vo AEO t veca= 3.8rad/sSubmitPrevious Answrs Request AnswerX Incorrect; Try Again: 2 attempts remaining32 ftProvide FeedbeckNext

Please go through the answer. To find the angular acceleration we have to apply equilibrium…

The 25-lb slender rod has a length of 6 ft Using a collar of nogligible mass, its end A is confined to move along the smooth circular bar of radus 32 ft End Brests on the floor, for which the coetficient of kinetic friction is pn =0.48 The bar is released from rest when 6- 30 (Eigure 1) Figure 1 of 1> oft 32 ft B

The 25-lb slender rod has a length of 6 ft Using a collar of nogligible mass, its end A is confined to move along the smooth circular bar of radus 32 ft End Brests on the floor, for which the coetficient of kinetic friction is pn =0.48 The bar is released from rest when 6- 30 (Eigure 1) Figure 1 of 1> oft 32 ft B

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.48P: Find the smallest distance d for which the hook will remain at rest when acted on by the force P....

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