The 2006 general Social Survey asked a large number of people how much time they spent watching TVeach day. The mean number of hours was 3.35 with a standard deviation of 2.78. Assume that in a sampleof 30 teenagers, the sample standard deviation of daily TV time is 2.37 hours, and that the population ofTV watching times is normally distributed. Under 10% significance level can you conclude that thepopulation standard deviation of TV watching times for teenagers is less than 2.78?Procedure: One variance x² Hypothesis TestAssumptions: (select everything that applies)O Normal populationO Simple random sampleO The number of positive and negative responses are both greater than 10O Sample size is greater than 30OPopulation standard deviation is knownO Population standard deviation is unknownPart 2 of 5Step 1. Hypotheses Set-Up:where ? v is the Select an answerand the units are ? VHo: Select an answer VHa: Select an answerand the test is Select an answer vStep 2. The significance level a =

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Answered: The 2006 general Social Survey asked a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Steve believes that his wife's cell phone battery does not last as long as his cell phone battery. On eleven different occasions, he measured the length of time his cell phone battery lasted and calculated that the mean was 16.4 hours with a standard deviation of 6.4 hours. He measured the length of time his wife's cell phone battery lasted on seven different occasions and calculated a mean of 23.3 hours with a standard deviation of 4.2 hours. Assume that the population variances are the same. Let Population 1 be the battery life of Steve's cell phone and Population 2 be the battery life of his wife's cell phone. Step 1 of 2: Construct a 90 % confidence interval for the true difference in mean battery life between Steve's cell phone and his wife's. Round the endpoints of the interval to one decimal place, if necessary.
Assume the average amount of caffeine consumed daily by adults is normally distributed with a mean of 260 mg and a standard deviation of 48 mg. In a random sample of 600 adults, how many consume at least 320 mg of caffeine daily?
The speed of cars on a specific road is normally distributed with a mean of 54 mph and a standard deviation of 3. The top 2.5% of cars are traveling at at least what mph?
Average adult Americans are about one inch taller but nearly a whopping 25 pounds heavier than they were in 1960, according to a report from the Centers for Disease Control and Prevention (CDC). City A is considered one of America's healthiest cities. Is the weight gain since 1960 similar in city A? A sample of n=25 adults suggested a mean increase of 22 pounds with a standard deviation of 9.4 pounds. Is City A significantly different in terms of weight gain since 1960? Complete and interpret 5 step hypothesis testing by hand at a 5% level of significance using a Z-test. Show each step and your work.
Suppose the distribution of typing speeds in words per minute for experienced typists can be approximated by a normal curve with a mean of 60 wpm and a standard deviation of 15 wpm. To be considered for a position an applicant needs to have a typing speed of at least 70 wpm. If 62 experienced typists apply for the job, how many of these would be considered based on their typing speed?
Airline companies are interested in the consistency of the number of babies on each flight, so that they have adequate safety equipment. They are also interested in the variation of the number of Babies. Suppose that an airline executive believes the standard deviation in the number of babies is 6 at the most. The airline conducts a survey. The results of the 23 flights surveyed give a samle mean of 8 with a sample standard deviation of 9. Test the executive's belief to see if it is accurate, or if it is actually greater at the a = 0.05 level. Ho:o = H:o Select an answer df = P-value = The p-value is... greater than a less than (or equal to) a This test statistic leads to a decision to... reject the null fail to reject the null accept the alternative accept the null As such, the final conclusion is that there Select an answer v sufficient evidence to conclude the standard deviation of the number of babies on airplanes is Select an answer than (?
6.10 Males 20 to 29 years old have a mean height of 69.4 inches with a standard deviation of 3.5 inches. Females 20 to 29 years old have a mean height of 64.1 inches with a standard deviation of 3.1 inches. Find the standardized variable for the heights of males. Find the standardized variable for the heights of females. For a 68‐inch‐tall person, find the value of the standardized variable for males. For a 68‐inch‐tall person, find the value of the standardized variable for females. Compare your answer with part (c) and comment.
Suppose the mean number of candies in a standard vending machine bag is 47.6 with a standard deviation of 1.3 . assume that the number of candies is normally distributed what percentage of bags have less than 45 candies?
Assume that adults have IQ scores that are normally distributed with a mean of 96 and a standard deviation 19.3. Find the first quartile Q1,which is the IQ score separating the bottom 25% from the top 75%. The first quartile is?
It is believed that nearsightedness affects 14% of children in a certain region. A school district tests the vision of 180 incoming kindergarten children. How many would be expected to be nearsighted? What is the standard deviation for the number of nearsighted children in such a group? You may assume that the children are independent of each other. The mean is? and the standard deviation is?
A study of commuting times reports the travel times to work of a random sample of 1068 employed adults in Chicago. The mean is x = 54.0 minutes and the standard deviation is s = 60.9 minutes. What is the standard error of the mean?
Steve believes that his wife's cell phone battery does not last as long as his cell phone battery. On eight different occasions, he measured the length of time his cell phone battery lasted and calculated that the mean was 19.7 hours with a standard deviation of 9.4 hours. He measured the length of time his wife's cell phone battery lasted on twelve different occasions and calculated a mean of 18.9 hours with a standard deviation of 5.3 hours. Assume that the population variances are the same. Let Population 1 be the battery life of Steve's cell phone and Population 2 be the battery life of his wife's cell phone. Step 1 of 2: Construct a 90 % confidence interval for the true difference in mean battery life between Steve's cell phone and his wife's. Round the endpoints of the interval to one decimal place, if necessary.

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