TD= event that the test result is dirtyTC event that the test result is cleanD = event that the person tested is actually dirtyC = event that the person tested is actually clean(a) Using the information in the quote, compute the following values.(1) P(TD|D)0.99(ii) P(TDIC)0.01(iii) P(C)0.99(iv) P(D)0.01(b) Use the probabilities from part (a) to construct a hypothetical 1,000 table. (Round your answers to the nearest integer.)DCTotalTDX 0.01XTCX(c) What is the value of P(TD) based on the table values?Total1,000(d) Use the information in the table to calculate the probability that a person is clean given that the test result is dirty, P(CITD).

Given: TD: event that the test result is dirty TC: event that the test result is clean D: event that…

Answered: that the test result is dirty TC= event…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(1 point) Matt thinks that he has a special relationship with the number 2. In particular, Matt thinks that he would roll a 2 with a fair 6-sided die more often than you'd expect by chance alone. Suppose p is the true proportion of the time Matt will roll a 2. (a) State the null and alternative hypotheses for testing Matt's claim. (Type the symbol "p" for the population proportion, whichever symbols you need of "", "=", "not =" and express any values as a fraction e.g. p = 1/3) Ho = Ha = (b) Now suppose Matt makesn = 34 rolls, and a 2 comes up 7 times out of the 34 rolls. Determine the P-value of the test: P-value = (C) Answer the question: Does this sample provide evidence at the 5 percent level that Matt rolls a 2 more often than you'd expect? (Type: Yes or No)
The events are approximately independent because 0.700 = 0.700. The events are not independent because 0.700 = 0.700. The events are approximately independent because 0.731 ≠ 0.700. The events are not independent because 0.731 ≠ 0.700.
supose that events E and F are independent with P(E) = 0.6 and P(F) = 0.7, What is P(E and F) (round answer to 2 decimal places) CS Scanned with CamScanner
Refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable x represents the number of girls among 8 children. Find the mean and standard deviation for the number of girls in 8 births. Click the icon to view the data table. The mean is µ = girl(s). (Round to one decimal place as needed.) The standard deviation is a girl(s). (Round to one decimal place as needed.)
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