A mixture containing 500[g] water and 100[g] ice is initially in thermal equilibrium at a temperature of 0[°C] in an insulated vessel. Then 200[g] of water vapor at 100[°C] is introduced into the vessel. Assume that the heat capacity of the vessel is negligible, further consider: Lmelting = 3.33*105[J/kg], Lvaporization = 22.60*105[J/kg] and specific heat of water cwater = 4200[J/kg*°C]. Determine the final composition of the system in grams and the final temperature.
A mixture containing 500[g] water and 100[g] ice is initially in thermal equilibrium at a temperature of 0[°C] in an insulated vessel. Then 200[g] of water vapor at 100[°C] is introduced into the vessel. Assume that the heat capacity of the vessel is negligible, further consider:
Lmelting = 3.33*105[J/kg], Lvaporization = 22.60*105[J/kg] and specific heat of water cwater = 4200[J/kg*°C].
Determine the final composition of the system in grams and the final temperature.
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Thank you, I find myself in a situation where the mass of the ice, for instance, 2 kilograms, is substantial enough to not melt due to the presence of vapor. How does this affect the calculation? Is it possible to resolve this?
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