Tests the claim that pi p2. Assume the samples are random and independent.D = 40; #2 = 18%3Dn = 90; n288a. Complete the table (use reduced fractions)P2b. Calculate the Z-test statistic using the standard error from part a.(use 2 decímal%3Dplaces)C. At a = 0.04 , Use the distribution table to find the critical values for the rejection regionZ = +d. What is your conclusion?O Reject the null hypothesis and support the claimO Accept the null hypothesis and support the claimO Accept the alternative hypothesis and reject the claimO Reject the alternative hypothesis and support the claimO Fail to reject the null hypothesis and do not support the claim

Answered: Tests the claim that pi # p2. Assume…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Some frozen food dinners were randomly selected from this week's production and destroyed in order to measure their actual calorie content. The claimed calorie content is 200. Here are the calorie counts for each frozen dinner selected: 193 213 193 211 202 192 208 204 186 199 199 186 Assume the distribution of calories is normal. (a) The test statistic (z/t) is ☐. Use two decimals. (b) Does the sample indicate that the mean calorie content is 200? Set a = (c) Find the P-value of the test in (a)-(b). = 0.01. ?
Find the critical value(s) and rejection region(s) for a left-tailed chi-square test with a sample size n=22 and level of significance α=0.05. LOADING... Click the icon to view the Chi-Square Distribution Table. Find the critical value(s). enter your response here (Round to three decimal places as needed. Use a comma to separate answers as needed.) Find the Rejection Region(s).
A drug company claims that their products’ contaminations never vary by more than 2%. Sample of 5 specimens were tested and the percentages of the purities are recorded as Observation no. 1 2 3 4 5 Percentages (%) 98.6 97.2 98.9 97.7 97.9 a. Do the sample data have enough proof to oppose the manufacturer’s claim? (HINT: take the range of 2% equal 4σ.) b. Find a 90% confidence interval for σ2.
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Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd = 0. x / 6 2 3 2 3 y / 8 7 9 7 14 Compute the absolute value of the test statistic. (Round your answer to nearest hundredth. Hint: The correct test statistic is positive.)
The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the coated portion subtracted from the amount of corrosion on the uncoated portion. Does this random sample provide sufficient reason to conclude that the coating is beneficial? Use a = 0.01 and assume normality. n- 40, Σd- 207, Σα? = 6199 (a) Find t. (Give your answer correct to two decimal places.) (ii) Find the p-value. (Give your answer correct to four decimal places.) (b) State the appropriate conclusion. O Reject the null hypothesis, there is significant evidence that the coating is beneficial. Reject the null hypothesis, there is not significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is not significant evidence that the coating is beneficial.
thill An experiment compares two different processes for producing steel plate. The measurements represent the thickness of the plate. The samples gave m = 8, X = 6.701, S1 = 0.108 n = 6, Y = 6.841, S2 = 0.155 %3D %3D Assume that the two populations are normal with equal variances, test Ho: H1 - H2 = 0 against H1 : µ1 - µ2#0 at a 0.05 significance level. 5.
Interpret a P-value: The manufacturer of a medication designed to lower blood pressure claims that the mean systolic blood pressure for people taking their medication is less than 135. To test this claim, blood pressure is measured for a sample of 500 people who are taking the medication. The P-value for testing Ho: μ = 135 versus H₁: µ< 135 is P = 0.001. a. The manufacturer concludes that because the P-value is very small, we can be fairly certain that the mean pressure is less than 135, but we cannot conclude that it is a lot smaller. Is this conclusion justified?
step by step please
Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is µd = 0. x / 734 13 y / 99 8 7 13 Compute the value of the test statistic. (Round your answer to nearest hundredth. Hint: The correct test statistic is positive.)
A student wants to determine if there is a difference in the pricing between two stores for health and beauty supplies. She recorded prices from both stores for each of 10 different products. Assuming that the conditions for conducting the test are satisfied, determine if there is a price difference between the two stores. Use the α = 0.1 level of significance. Complete parts (a) through (d) below. A B C D E F G H I J 5.95 7.41 3.76 1.74 1.78 2.88 4.72 3.13 2.98 3.75 Store 1 Store 5.97 7.95 3.94 1.78 1.92 2.49 4.71 3.74 2.95 3.69 2 (a) What type of test should be used? Choose the correct answer below. A. A hypothesis test regarding the difference of two means using a matched-pairs design. B. A hypothesis test regarding two population standard deviations. OC. A hypothesis test regarding the difference between two population proportions from independent samples. OD. A hypothesis test regarding the difference of two means using Welch's approximate t. (b) Determine the null and alternative…
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