Tests the claim that 41 2. Assume the samples are random and independent.01 = 0.7; o2 = 0.64T1 = 39.56 ; z2 = 39.09%3Dni = 44; n2 = 31%3D%3Da. Calculate the Standard Error oz,-, =(3 decimal places)b. Calculate the Z-test statistic using the standard error from part a. 2 =(2 decimal places)C. At a = 0.06 , Use the distribution table to find the critical values for the rejection region(3 decimal places)d. What is your conclusion?O Accept the null hypothesis and support the claimO Reject the alternative hypothesis and support the claimO Reject the null hypothesis and support the claimO Fail to reject the null hypothesis and do not support the claimAccept the alternative hypothesis and reject the claim

Answered: Tests the claim that 41 µ2. Assume the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A. Compute the test statistics. Round to three decimal places as needed.
The average family size was reported as 3.18. A random sample of families in a particular school district resulted in the following family sizes: 5 4 4 3 6 4 3 3 5 5 6 3 3 2 7 4 5 2 3 2 At =α 0.10, does the average family size differ from the national average? Assume the population is normally distributed. Find the -value. Round answer to four decimal places. Make a decision and Summarize your answer.
10.2.3 WP GO Tutorial The diameter of steel rods manufactured on two different extrusion machines is being investigated. Two random samples of sizes n₁ = 15 and n₂ = 17 are selected, and the sample means and sample variances are x₁ = 8.73, ² 0.35,₂ = 8.68, and s² = 0.40, respectively. Assume that o and that the data are drawn from a normal distribution. - = 0 a. Is there evidence to support the claim that the two machines produce rods with different mean diameters? Use α = 0.05 in arriving at this conclusion. Find the P-value. b. Construct a 95% confidence interval for the difference in mean rod diameter. Interpret this interval.
Please solve the problem manually
Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd = 0. x / 6 2 3 2 3 y / 8 7 9 7 14 Compute the absolute value of the test statistic. (Round your answer to nearest hundredth. Hint: The correct test statistic is positive.)
HELP ASAP. info is given in the pic. 8) At which value for alpha (type I) error is the ANOVA model statistically significant?A) 0.05B) 0.025C) 0.01D) 0.005E All of the above 9) When using Fisher's LSD test with a = 0.05 to compare age categories, what is the LSDvalue when comparing the Under 20 group to the 20 to 29 group?A) 9.283B) -0.376C) 2.120D) 11.272E) -2.0 10) Treating the Age factor as a random effect, use the components of variance model toestimate the variance in systolic blood pressure (Y).A) 8.42B) 33.69C) 70.67D) 104.37E) 239.13
The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the coated portion subtracted from the amount of corrosion on the uncoated portion. Does this random sample provide sufficient reason to conclude that the coating is beneficial? Use a = 0.01 and assume normality. n- 40, Σd- 207, Σα? = 6199 (a) Find t. (Give your answer correct to two decimal places.) (ii) Find the p-value. (Give your answer correct to four decimal places.) (b) State the appropriate conclusion. O Reject the null hypothesis, there is significant evidence that the coating is beneficial. Reject the null hypothesis, there is not significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is not significant evidence that the coating is beneficial.
6
a. Compute the p-value for the test (use R). Round to the nearest 3rd decimal place, 0.xxx. b. Make and justify a statistical decision at the α= 0.15 significance level and state your conclu-sions in context of the problem.
Calculate the missing values in the Stata output (SKIP E!!!). Two-sample t test with A variances X y combined diff Obs Ho: diff = 0 49 30 79 diff = mean(x) Ha: diff |t|) = Std. Dev. 6.5 7.4 6.935314 G E [95% Conf. Intervall 40.33298 39.62126 C F degrees of freedom = 44.86702 Pr{T > t) 42.72811 1.6996 77 Ha: diff > 0 H
As a bonus assignment a former student checked if your professor gave a statisticallysignificant difference in grades between his male and female students. She based herstudy based on grades assigned in intermediate Econ courses (Econ 303, 305 and 317)and her sample included nm = 485 male students and nf = 264 female students. Theaverage grades received were xm = 84.6 and xf = 85.8 The population standad deviation were σ m = 12.0 and σ f = 11.4 8. From the same extra-credit study as in question 7 see above, this former student found that the proportion of female students in principle courses (Econ 203, 205) was ?̅? = 0.380, while the proportion of female students in intermediate courses (Econ 303, 305, 317) was ?̅? = 0.352. The principle courses sample size was np = 782, while the intermediate courses sample size was ni = 749. Test the hypothesis that female students are less in intermediate courses using a 90% confidence level and the p-value approach.
Suppose in a local Kindergarten through 12th grade (K -12) school district, 49% of the population favor a charter school for grades K through 5. A simple random sample of 144 is surveyed. a. Find the mean and the standard deviation of X of B(144, 0.49). Round off to 4 decimal places. O = b. Now approximate X of B(144, 0.49) using the normal approximation with the random variable Y and the table. Round off to 4 decimal places. Y - N( c. Find the probability that at most 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X 75) - P(Y > a (Z > e. Find the probability that exactly 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X = 81) - P(

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