test was made of h0: u1=u2 versus h0: u1
Q: Use the figure to the right, which shows the percentages of adults from several countries who favor…
A: For country C n=1024,p hat =0.45 For country D n =1078 ,p hat = 0.41
Q: A survey of 62 men found that 12 have a social media account. Another survey of 57 women found that…
A: Men are taken as group 1. Women are taken as group 2. Given: n1=62x1=12n2=57x2=40α=0.07
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A: The complete solution and result is in images uploaded below. Thanks!
Q: se technology to calculate the P-value P-value = (Round to three decimal places as needed.)
A: Given that Sample size n1=1120 , n2=1048 Sample proportion p1^=0.47 , p2^=0.46
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A: We have given that p = 40% = 0.40 n = 2730x = 1130p̂ = x/n = 1130/2370 = 0.4139Significance level…
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Q: If Julio’s score on an IQ test is 73, what is his score as a z score? (M = 100, s = 15)
A: The z-score is obtained below: From the given information, the Julio’s score on an IQ test is 73.…
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A: Assume that p as the true proportion of all accidents.
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A:
Q: What is the value of SX + 1 for the scores 1, 6, 3?
A: The sum of scores is 1+6+3 = 10. That is, SX = 10
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Q: AN OUTDOOR HOT DOG VENDOR SELLS AN AVERAGE OF 60 HOT DOGS PER DAY IN DRY WEATHER AND AN AVERAGE OF…
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A: Outcomes Frequency Vennila227Chocolate228Butter Pecan107Strawberry85Other283Total930
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A: Given that Sample sizes for Country C and D n1=1024 , n2= 1078 Level of significance =alpha = 0.09
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Q: O E Ho: P1 P2 D D. Ho: P1 2 P2 H: P <P2 H, P, SP2 H P, 2P2 ind the standardized test statistic. z=…
A: Given that Sample sizes n1=1120 , n2=1048 Sample proportion p1^ =0.47 , p2^=0.46
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- A student pursuing a degree in English as a second language believes the proportion female factory workers who can't speak English is less than the proportion of male factory workers who can't speak English. To test her claim she randomly selects 313 female factory workers and out of them 48 could not speak English. She then randomly selects 400 male factory workers and out of them 43 could not speak English. Test her claim at a=0.05 to see if she was right. The correct hypotheses are: O Ho:PF Рм (сclaim) O Ho:PF 2 PM HA:PF < PM(claim) O Ho:PF = pM HA:PF + PM(claim) Since the level of significance is 0.10 the critical value is -1.282 The test statistic is: (round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho The final conclusion is that: O There is enough evidence to reject the claim that the proportion female factory workers who can't speak English is less than the proportion of male factory workers who can't speak…Aspirin prevents blood from clotting and helps prevent strokes. The Second European Stroke Prevention Study asked whether adding another anticlotting drug named dipyridamole would make a difference for patients who had already had a stroke. Here are the data on strokes during the two years of the study: Aspirin alone Apsirin & Dipyridamole Number of Patients This test is two-t led. What is the test statistic? -2.700 200 = V 200 Is there a significant difference in the proportion of strokes in the two groups? Test at a = 0.05. Round your answers to three decimal places, and round any interim calculations to four decimal places. #v Fill in the hypotheses below where p₁ denotes the proportion of patients in the aspirin group who suffered a stroke and på denotes the proportion of patients in the aspirin & dipyridamole group who suffered a stroke. Ho: P₁ Ha: P₁ Number of Strokes P₂ 60 P₂ 86 Using your answer from the previous question, find the p-value. ▼ Part 2 of 4 Part 3 of 4From a Gallup Poll: Among 990 survey subjects, 5.6 % have an alcoholic drink every day. x = nothing (round off to a whole number)
- A telemarketer is trying two different sales pitches to sell a carpetcleaning service. For Sales Pitch I, he contacted 175 people and 62 of these people bought the cleaning service. For Sales Pitch II, he contacted 154 people and 45 of these people bought the cleaning service. Does this indicate that there is any difference in the population proportions of the people who will buy the cleaning service, depending on which sales pitch he uses? Use α = 0.05.A survey found that in a sample of 100 families, 37 owned cats. A survey done 5 years ago found that in a sample of 80 families, 34 owned cats. At ? = 0.05 has the proportion of cat owners changed over the 5-year period?Use the figure to the right, which shows the percentages of adults from several countries who favor building new nuclear power plants in their country. The survey included random samples of 1051 adults from Country A, 1120 adults from Country B, 1048 adults from Country C, and 1013 adults from Country D. At a=0.05, can you support the claim that the proportion of adults in Country B who favor building new nuclear power plants in their country is different from the proportion of adults from Country C who favor building new nudear power plants in their country? Assume the random samples are independent. Country A 53% Country B 47% Country C 46% OCountry D 34% Identify the claim and state Ho and H- The claim is "the proportion of adults in Country B who favor building new nuclear power plants in their country is different than the proportion of adults from Country C who favor building new nuclear power plants in their country." Let p, represent the population proportion for Country B and…
- The pass result of fifty students who took up a class test is given below: Marks Number of Students 4 8 5 10 9. 7 4 9. 3 If the average marks for all the fifty students were 5.16, find out the average marks of ti students who failed.The death rate per 100,000 for lung cancer is 7 among non-smokers and 71 among smokers. The death rate per 100,000 for coronary thrombosis is 422 among non-smokers and 599 among smokers. The prevalence of smoking in the population is 55%.Among smokers, the etiologic fraction of disease due to smoking is: A. 0.90 for lung cancer and 0.88 for coronary thrombosis. B. 0.89 for lung cancer and 0.29 for coronary thrombosis. C. 0.89 for lung cancer and 0.88 for coronary thrombosis. D. cannot be determined from the information provided. E. 0.90 for lung cancer and 0.29 for coronary thrombosis.Last week, a political campaign aired a new TV ad promoting its candidate. The ad was aired a different number of times depending on the region. To decide how many times to air the ad next week, the campaign manager looked at the impact the ad had made in the different regions. She tracked the number of times the ad had run in each region, x, and the increase of the candidate's approval rating in those regions, y. Ads run Approval rating increase 6 20 9. 6 12 18 14 10 18 19 Round your answer to the nearest thousandth.
- A student pursuing a degree in English as a second language believes the proportion female factory workers who can't speak English is less than the proportion of male factory workers who can't speak English. To test her claim she randomly selects 373 female factory workers and out of them 43 could not speak English. She then randomly selects 215 male factory workers and out of them 65 could not speak English. Test her claim at .=0.05 to see if she was right. The correct hypotheses are: H : PF Pu (claim) H : PF 2 PM HA: PF < Pr (claim) H : PF = PM HA: PF + PM (claim) Since the level of signficance s0.05 the critical value is-1.64s The test statistic is pound to 3 places) The pvalue is round to 3 places) The decision can be made to oreject H, odo not reject í, The final conclusion is that: There is enough evidence to reject the claim that the proportion female factory workers who can't speak English is less than the proportion of male factory workers who can't speak English. There is…How would I identify the p-value?