Test the series below for convergence using the Ratio Test. (-1) "10²+1 (2n + 1)! n=0 The limit of the ratio test simplifies to lim f(n)| where f(n) = The limit is: 0 (enter oo for infinity if needed) Based on this, the series Converges Question Help: Message instructor Add Work

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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### Ratio Test for Series Convergence

**Series to Test:**

\[ \sum_{n=0}^{\infty} \frac{(-1)^n 10^{2n+1}}{(2n+1)!} \]

**Procedure Using the Ratio Test:**

1. Identify \( f(n) \) and the limit you need to evaluate.
2. Compute the limit \( \lim_{n \to \infty} \left| \frac{f(n+1)}{f(n)} \right| \).

**Form of \( f(n) \):**

The function \( f(n) \) here represents each term in the series:

\[ f(n) = \frac{(-1)^n 10^{2n+1}}{(2n+1)!} \]

**Simplifying the Limit:**

\[ \lim_{n \to \infty} \left| \frac{f(n+1)}{f(n)} \right| \]

**Limit Calculation:**

Enter the value of the limit \( \frac{f(n+1)}{f(n)} \) which we are testing for convergence. In specific problems like this, you often compute it step-by-step:

\[ \lim_{n \to \infty} \left| \frac{\frac{(-1)^{n+1} 10^{2(n+1)+1}}{(2(n+1)+1)!}}{\frac{(-1)^n 10^{2n+1}}{(2n+1)!}} \right| \]

Here you would then enter the calculated limit:

\[ \text{The limit is: } \boxed{0} \]

**Conclusion Based on Limit:**

Finally, based on the ratio test, state whether the series converges or diverges. For the given limit:

\[ \boxed{0} \]

The series:

\[ \boxed{\text{Converges}} \]

**Support and Further Help:**

For additional questions or help, you can:

- **Message Instructor:** Get in touch with your instructor directly for personalized assistance.
- **Add Work:** Include your calculations or steps you followed for a detailed review.

*Note: If there were any graphs or diagrams, they should be explained here, but this specific example does not include any graphical elements.*
Transcribed Image Text:### Ratio Test for Series Convergence **Series to Test:** \[ \sum_{n=0}^{\infty} \frac{(-1)^n 10^{2n+1}}{(2n+1)!} \] **Procedure Using the Ratio Test:** 1. Identify \( f(n) \) and the limit you need to evaluate. 2. Compute the limit \( \lim_{n \to \infty} \left| \frac{f(n+1)}{f(n)} \right| \). **Form of \( f(n) \):** The function \( f(n) \) here represents each term in the series: \[ f(n) = \frac{(-1)^n 10^{2n+1}}{(2n+1)!} \] **Simplifying the Limit:** \[ \lim_{n \to \infty} \left| \frac{f(n+1)}{f(n)} \right| \] **Limit Calculation:** Enter the value of the limit \( \frac{f(n+1)}{f(n)} \) which we are testing for convergence. In specific problems like this, you often compute it step-by-step: \[ \lim_{n \to \infty} \left| \frac{\frac{(-1)^{n+1} 10^{2(n+1)+1}}{(2(n+1)+1)!}}{\frac{(-1)^n 10^{2n+1}}{(2n+1)!}} \right| \] Here you would then enter the calculated limit: \[ \text{The limit is: } \boxed{0} \] **Conclusion Based on Limit:** Finally, based on the ratio test, state whether the series converges or diverges. For the given limit: \[ \boxed{0} \] The series: \[ \boxed{\text{Converges}} \] **Support and Further Help:** For additional questions or help, you can: - **Message Instructor:** Get in touch with your instructor directly for personalized assistance. - **Add Work:** Include your calculations or steps you followed for a detailed review. *Note: If there were any graphs or diagrams, they should be explained here, but this specific example does not include any graphical elements.*
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