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Test the pair of events B and F for independence based on the following table. B 0.04 0.03 0.03 0.10 D E F Total A 0.12 0.09 0.09 0.30 с 0.24 0.18 0.18 0.60 Total 0.40 0.30 0.30 1.00 Are B and F independent or dependent and why? Select the correct answer below and fill in the answer boxes to complete your choice. O A. B and F are dependent because P(BNF) does not equal P(B)P(F). P(BNF) = and P(B)P(F)= O B. B and F are dependent because P(BNF) equals P(B)P(F). P(BNF)= and P(B)P(F) = OC. B and F are independent because P(BNF) does not equal P(B)P(F). P(BNF)= and P(B)P(F) = O D. B and F are independent because P(BNF) equals P(B)P(F). P(BNF) = and P(B)P(F) =

Test the pair of events B and F for independence based on the following table. B 0.04 0.03 0.03 0.10 D E F Total A 0.12 0.09 0.09 0.30 с 0.24 0.18 0.18 0.60 Total 0.40 0.30 0.30 1.00 Are B and F independent or dependent and why? Select the correct answer below and fill in the answer boxes to complete your choice. O A. B and F are dependent because P(BNF) does not equal P(B)P(F). P(BNF) = and P(B)P(F)= O B. B and F are dependent because P(BNF) equals P(B)P(F). P(BNF)= and P(B)P(F) = OC. B and F are independent because P(BNF) does not equal P(B)P(F). P(BNF)= and P(B)P(F) = O D. B and F are independent because P(BNF) equals P(B)P(F). P(BNF) = and P(B)P(F) =

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Table for Testing Independence of Events B and F** The given table provides the distribution of events across different categories: | | A | B | C | Total | |-------|------|------|------|-------| | D | 0.12 | 0.04 | 0.24 | 0.40 | | E | 0.09 | 0.03 | 0.18 | 0.30 | | F | 0.09 | 0.03 | 0.18 | 0.30 | | Total | 0.30 | 0.10 | 0.60 | 1.00 | --- **Question:** Are B and F independent or dependent and why? Select the correct answer below and fill in the answer boxes to complete your choice. - **A.** B and F are dependent because P(B∩F) does not equal P(B)P(F). P(B∩F) = [Box] and P(B)P(F) = [Box]. - **B.** B and F are dependent because P(B∩F) equals P(B)P(F). P(B∩F) = [Box] and P(B)P(F) = [Box]. - **C.** B and F are independent because P(B∩F) does not equal P(B)P(F). P(B∩F) = [Box] and P(B)P(F) = [Box]. - **D.** B and F are independent because P(B∩F) equals P(B)P(F). P(B∩F) = [Box] and P(B)P(F) = [Box].
Transcribed Image Text:**Table for Testing Independence of Events B and F** The given table provides the distribution of events across different categories: | | A | B | C | Total | |-------|------|------|------|-------| | D | 0.12 | 0.04 | 0.24 | 0.40 | | E | 0.09 | 0.03 | 0.18 | 0.30 | | F | 0.09 | 0.03 | 0.18 | 0.30 | | Total | 0.30 | 0.10 | 0.60 | 1.00 | --- **Question:** Are B and F independent or dependent and why? Select the correct answer below and fill in the answer boxes to complete your choice. - **A.** B and F are dependent because P(B∩F) does not equal P(B)P(F). P(B∩F) = [Box] and P(B)P(F) = [Box]. - **B.** B and F are dependent because P(B∩F) equals P(B)P(F). P(B∩F) = [Box] and P(B)P(F) = [Box]. - **C.** B and F are independent because P(B∩F) does not equal P(B)P(F). P(B∩F) = [Box] and P(B)P(F) = [Box]. - **D.** B and F are independent because P(B∩F) equals P(B)P(F). P(B∩F) = [Box] and P(B)P(F) = [Box].
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