(c)A random sample of 200 married clinical academic doctors, all retired, was classifiedaccording to seniority and number of children:Children:Seniority:0-23-4More than 4Academic clinical fellow322516Clinical lecturer441822Clinical research fellow22813Test the hypothesis (Ho: The size of family is independent of level of seniority) that thesize of a family is independent of the level of seniority attained by the doctors at the0.05 level of significance. Use the chi-squared critical value approach. (а)The performances in a statistics course with 100 students for a particular semester wereas follows:GradeAВFNumber of students182532205At the 0.05 level of significance, test the hypothesis that the distribution of performanceis uniform (Ho: The data is uniformly distributed). Use the chi-squared critical valueapproach.(b)Given the variance of a chi-squared distribution is 2v, where v is the degrees offreedom. Show that the variance of S for random samples of size n from a normalpopulation decreases as n increases.

Here AS PER POLICY I HAVE CALCULATED FIRST MAIN QUESTION PLZ REPOST FOR REMAINING Define events A…

Answered: Test the hypothesis (Ho: The size of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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“Passive and Active Smoke” in Appendix B includes cotinine levels measured in a group of nonsmokers exposed to tobacco smoke (n = 40, Mean = 60.58 ng>mL, s = 138.08 ng>mL) and a group of nonsmokers not exposed to tobacco smoke (n = 40, Mean = 16.35 ng>mL, s = 62.53 ng>mL). Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed by the body, cotinine is produced. Use a 0.05 significance level to test the claim that nonsmokers exposed to tobacco smoke have a higher mean cotinine level than nonsmokers not exposed to tobacco smoke. 1. Construct a confidence interval estimate of the difference betwen the mean continen levels fo the two groups of nonsmokers. What confidence level would be appropriate? 2. Find the margin of error E using the formula. 3. What is the confidence interval? Explain the meaning of the confidence interal and what the limit represents.
The side effects of a new drug are being tested against a placebo. A random sample of 565 patients yields the results in the table below. At a significance level of a = to conclude that the treatment is not causing at least some of the side effects? Hint: Use the Placebo Column as the E, Side-Effect Headache Nausea 0.0465, is there enough evidence Drug Placebo 422 395 111 104 Fatigue Increased Depression 112 Increased Infections 331 354 84 28 13 (a) Find Ho and Ha (b) Find the critical value (c) Find the test value (d) Accept or rejection Ho
Positive autocorrelation in control charts has which of the following characteristics? A. Is observed when large values follow large values B. Can cause high false-negative rates for special cause variation C. Is seen when large values follow small values D. Is a rare occurrence with measurements of a same patient or provider over time
A study was done on the type of automobile owned by women and men. the data are shown. At the 0.10 level of significance, is there a relationship between the type of automobile owned and the gender of the individual? What is the appropriate decision for this problem? Luxury Large Midsize small Men 15 9 49 27 Women 9 6 62 14 What is the p-value? What is the critical value? What is the expected value for women who buy midsize cars? What is the chi-squared value? (2 decimal places)
BONUS: Explain (with examples if possible) the relationship between the p-value, alpha, your obtained statistic and your critical value.
A study was conducted to investigate drinking problems among college students. In 1983, a group of students were asked whether they had ever driven an automobile while drinking. In 1987, after the legal drinking age was raised, a different group of college students was asked the same question. The results are as shown in the table below. Test to compare the proportions of students with a drinking problem at 0.05 level of significance, 1987 versus 1983; and provide the chi-squared statistic value below (in 2 decimal places). Year Drove while drinking Yes No 1983 1,258 1,355 1987 994 1,643
A geneticist was curious about the relationship between gender and dominant hand. They surveyed a random sample of 500 people. Here is a summary of the responses and the results from a chi-squared test: Chi-square test: Dominant hand vs. gender Men Women Right 207 227 Expected 208.32 225.68 Left 21 27 Expected 23.04 24.96 Ambidextrous 12 - Expected 8.64 9.36 X%3D2.876, DF 2, P-value 0.237 Assume that all conditions for inference were met. At the a = 0.05 significance level, what is the most appropriate conclusion to draw from this test? O This is convincing evidence that the distribution of dominant hand differs between the genders. O This isn't enough evidence to say that the distribution of dominant hand differs between the genders. O This is convincing evidence that dominant hand and gender are not independent. OThey lack evidence to say that dominant hand and gender are not independent. O Gender causes people to be more likely to be left- or right-handed.
A local veterinarian uses Z-scores to determine if newborn puppies of certain breeds are severely underweight, underweight, overweight, severely overweight, or within a typical weight range for their breed. Z-score Diagnosis Severely underweight Between -4.0 and -3.0 Underweight Less than -4.0 Between -3.0 and 3.0 Within the normal range Between 3.0 and 4.0 Overweight Severely overweight Greater than 4.0 Breed Mean (pounds) Standard deviation (pounds) Siberian Husky 23.2 2.5 Golden Retriever 31.5 2.1 Chow Chow 18.5 2.4 Shiba Inu 13.9 1.2 (a) What values would be considered to be normal for a hypothetical Siberian Husky puppy? Between and Enter an integer or decimal number (more. Report these answers to one decimal place (nearest tenth). (b) Show calculations and explain your reasoning.
54% of students entering four-year colleges receive a degree within six years. Is this percent smaller for students who play intramural sports? 415 of the 800 students who played intramural sports received a degree within six years. What can be concluded at the 0.05 level of significance? H0: p = 0.54 Ha: p [ Select ] ["<", "Not Equal To", ">"] 0.54 p-Value = [ Select ] ["0.03", "0.23", "0.06", "0.11"] [ Select ] ["Fail to Reject Ho", "Reject Ho"] Conclusion: There is [ Select ] ["statistically significant", "insufficient"] evidence to make the conclusion that the population proportion of college students who play intramural sports that receive a degree within six years is less than 0.54. p-Value Interpretation: If the proportion of college students who play intramural sports that receive a degree within six yeas is equal to [ Select ] ["0.52", "0.54", "0.48", "0.50"]and if another study was done with a new randomly selected collection of…
Modified True or False VIF is a measure of how much the variance of the estimated regression coefficients are inflated.
Devise a hypotheses for the research question: Is there singificant correlation between students height and typical amount of sleep a student gets per night? Identify the appropriate statistical test using alpha = 0.05. Perform the statistical test. Use descriptive statistics to describe the variables both numerically and graphically. Height (whole inches) Sleep (minutes) 60 360 62 400 66 420 68 440 68 540 70 480 72 320 75 440 66 360 63 420 69 420 75 390 69 360 67 480 69 360 73 360 69 480 70 420 68 360 63 480 69 270 68 360 71 420 71 360 62 420

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Test the hypothesis (Ho: The size of family is independent of level of seniority) that the size of a family is independent of the level of seniority attained by the doctors at the 0.05 level of significance. Use the chi-squared critical value approach.