Test the claim that the population mean weight (in pounds) of rainbow trout is more than the population mean weight of brook trout. A random sample of 18 rainbow trout yields a mean weight of 1.53 pounds and standard deviation of 0.4, while a random sample of 24 brook trout yields a mean weight of 1.12 pounds and a standard deviation of 0.2. Use a = 0.05. Let Population 1 be the rainbow trout, and assume that trout weights are normally distributed. 1. The fact that trout weights are normally distributed is important in this test because: O both sample sizes are less than thirty O this is a T-test O this is a Z-test O both sample means are less than thirty The hypotheses are: O Ho:p1 = p2; Ha: p1 # p2 O Ho:p1 2 p2; Ha:p1 < p2 O Ho:p1 < p2; Ha:p1 > p2 O Ho:p = H2; Ha: µ1 # µ2 O Ho:p < p2; Ha: µ1 > µ2 O Ho:µ P2; Ha: µ1 < µ2 2. This is a O rightO twoO left tailed test and the distribution used is OZ since testing two proportions OT since both o values are not known OZ since both o values are known

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Counting Theory

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