If E[X] = 2 and Var(X) = 5, then E[(4 + 5X)2] = and Var(5 + 4X) = %3D
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![If E[X] = 2 and Var(X) = 5, then
%3D
%3D
E[(4 +5X)2] =
%3D
and
Var(5+4X) =
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe28104ce-de99-450a-a1b7-64972e30f7c2%2F69f56766-c8d8-424c-8159-5ba396449a33%2F4b853dd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:If E[X] = 2 and Var(X) = 5, then
%3D
%3D
E[(4 +5X)2] =
%3D
and
Var(5+4X) =
%3D
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