Test the claim that the mean GPA of night students is significantly different than 2.8 at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p 2 0.7 Họ :p< 0.7 Ho:µ < 2.8 Ho:µ > 2.8 Ho:µ = 2.8 Ho:p = 0.7 H1:p < 0.7 H:p> 0.7 H1: µ > 2.8 H1:µ < 2.8 H1: µ # 2.8 H1:p# 0.7 The test is: left-tailed two-tailed right-tailed Based on a sample of 65 people, the sample mean GPA was 2.81 with a standard deviation of 0.03 The test statistic is: (to 2 decimals) tv
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- Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.02 significance level. (a) The null and alternative hypothesis would be: H0:πN=πD H1:πN<πD H0:μN=μD H1:μN<μD H0:μN=μD H1:μN>μD H0:πN=πD H1:πN>πD H0:πN=πD H1:πN≠πD H0:μN=μD H1:μN≠μD (b) The test is: right-tailed left-tailed two-tailed The sample consisted of 45 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 45 day students, with a sample mean GPA of 3.01 and a standard deviation of 0.03. (c) The t-score is: (Round to 2 decimal places.) (d) The p-value is: (Round to 4 decimal places.) (e) Based on this we conclude: null is plausible strong support for the alternativeTest the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 The test is: right-tailed left-tailed two-tailed Based on a sample of 200 people, 87% owned catsThe p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesisIn the past, the mean lifetime for a certain type of flashlight battery has been 9.5 hours. The manufacturer has introduced a change in the production method and wants to perform a significance test to determine whether the mean lifetime has increased as a result. The hypotheses are: null: μ = 9.5 hours alternative: u 9.5 hours Suppose that the results of a significance test result in a rejection of the null hypothesis. If we later find out that the true population running time was actually equal to 10.5, what error has been committed? Type I and Type II error Type II error no error Type I error
- Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .005 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF The test is: right-tailed left-tailed two-tailed Based on a sample of 80 men, 25% owned catsBased on a sample of 60 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesisTest the claim that the proportion of men who own cats is smaller than 90% at the .05 significance level.The null and alternative hypothesis would be: H0:μ=0.9H0:μ=0.9H1:μ>0.9H1:μ>0.9 H0:p=0.9H0:p=0.9H1:p>0.9H1:p>0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:μ=0.9H0:μ=0.9H1:μ<0.9H1:μ<0.9 H0:p=0.9H0:p=0.9H1:p<0.9H1:p<0.9 The test is: right-tailed two-tailed left-tailed Based on a sample of 65 people, 87% owned catsThe test statistic is: (to 2 decimals)The critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis I dont understand this.Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: two-tailed right-tailed left-tailed Based on a sample of 60 men, 30% owned catsBased on a sample of 40 women, 40% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Check AnswerQuestion 14
- Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.05 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: right-tailed two-tailed left-tailed Based on a sample of 40 men, 40% owned catsBased on a sample of 40 women, 60% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesisTest the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.1 significance level. The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 45% owned catsBased on a sample of 40 women, 70% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesisTest the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: left-tailed two-tailed right-tailed Based on a sample of 20 men, 40% owned catsBased on a sample of 40 women, 55% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
- Test the claim that the mean GPA of night students is larger than 2.1 at the 0.01 significance level. The null and alternative hypotheses would be: 0.525 Ho: u = 2.1 Ho: µ = 2.1 Ho:µ = 2.1 Ho:p 0.525 Ho:p 0.525 H:p> 0.525 H1:p+ 2.1 H:µ > 2.1 H:µ < 2.1 H1:p< 0.525 H :p + 0.525 The test is: left-tailed two-tailed right-tailed Based on a sample of 38 people, the sample mean GPA was 2.11 with a standard deviation of 0.2 The p-value is: (to 3 decimals) The significance level is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Question Help: Message instructor Submit Question N D archTest the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 20 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesisTest the claim that the proportion of people who own cats is smaller than 40% at the 0.05 significance level.The null and alternative hypothesis would be: H0:μ≥0.4H0:μ≥0.4H1:μ<0.4H1:μ<0.4 H0:μ=0.4H0:μ=0.4H1:μ≠0.4H1:μ≠0.4 H0:p≥0.4H0:p≥0.4H1:p<0.4H1:p<0.4 H0:p≤0.4H0:p≤0.4H1:p>0.4H1:p>0.4 H0:p=0.4H0:p=0.4H1:p≠0.4H1:p≠0.4 H0:μ≤0.4H0:μ≤0.4H1:μ>0.4H1:μ>0.4 The test is: left-tailed two-tailed right-tailed Based on a sample of 100 people, 33% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis