Test the claim that the mean GPA of night students is significantly different than 2.4 at the 0.2 significance level. The null and alternative hypothesis would be: Ho:p = 0.6 H1:p + 0.6 Ho: µ = 2.4 H1:µ + 2.4 O Ho:p = 0.6 H1:p < 0.6 Ο H0: μ 2.4 H1 :µ < 2.4

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**Test the Claim for Mean GPA of Night Students**

Objective: Test the claim that the mean GPA of night students is significantly different from 2.4 at a 0.2 significance level.

---

**Hypotheses:**

Choose the correct null and alternative hypotheses:

- \( H_0: p = 0.6 \)
  
  \( H_1: p \neq 0.6 \)

- \( H_0: \mu = 2.4 \)
  
  \( H_1: \mu \neq 2.4 \)

- \( H_0: p = 0.6 \)
  
  \( H_1: p < 0.6 \)

- \( H_0: \mu = 2.4 \)
  
  \( H_1: \mu < 2.4 \)

- \( H_0: p = 0.6 \)
  
  \( H_1: p > 0.6 \)

- \( H_0: \mu = 2.4 \)
  
  \( H_1: \mu > 2.4 \)

---

**Sample Data:**

- Sample size: 40
- Sample mean GPA: 2.37
- Standard deviation: 0.05

---

**Calculations:**

- **Test Statistic:**

  Enter the calculated test statistic (to 3 decimals).

- **Positive Critical Value:**

  Enter the positive critical value (to 3 decimals).

---

**Decision:**

Based on the calculations, choose one of the following:

- Reject the null hypothesis.

- Fail to reject the null hypothesis.

For further assistance, click on "Message instructor."
Transcribed Image Text:**Test the Claim for Mean GPA of Night Students** Objective: Test the claim that the mean GPA of night students is significantly different from 2.4 at a 0.2 significance level. --- **Hypotheses:** Choose the correct null and alternative hypotheses: - \( H_0: p = 0.6 \) \( H_1: p \neq 0.6 \) - \( H_0: \mu = 2.4 \) \( H_1: \mu \neq 2.4 \) - \( H_0: p = 0.6 \) \( H_1: p < 0.6 \) - \( H_0: \mu = 2.4 \) \( H_1: \mu < 2.4 \) - \( H_0: p = 0.6 \) \( H_1: p > 0.6 \) - \( H_0: \mu = 2.4 \) \( H_1: \mu > 2.4 \) --- **Sample Data:** - Sample size: 40 - Sample mean GPA: 2.37 - Standard deviation: 0.05 --- **Calculations:** - **Test Statistic:** Enter the calculated test statistic (to 3 decimals). - **Positive Critical Value:** Enter the positive critical value (to 3 decimals). --- **Decision:** Based on the calculations, choose one of the following: - Reject the null hypothesis. - Fail to reject the null hypothesis. For further assistance, click on "Message instructor."
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