Question HHelpTest the claim about the difference between two population means u, and H, at the level of significance a., Assume the samples are random and independent, and the populations are normally distributed.Claim: u, =µ2; a = 0.01Population statistics: o, = 3.3, o2 = 1.5Sample statistics: x, = 18, n, = 30, X2 = 20, n2 = 29Determine the alternative hypothesis.Ha: H1Determine the standardized test statistic.(Round to two decimal places as needed.)z=Determine the P-value.P-value = (Round to three decimal places as needed.)What is the proper decision?OA Enil tn rminnt UThore in onouah idene at the 10. louel of eianifinannn to reinnt the alaim(? Question Help ▼Test the claim about the difference between two population means u, and u, at the level of significance a. Assume the samples are random and independent, and the populations are normally distributed.Claim: µ, = µ2; a = 0.01Population statistics: 0, =3.3, o2 = 1.5Sample statistics: x, = 18, n, = 30, x2 = 20, n2 = 29Determine the P-value.P-value = (Round to three decimal places as needed.)What is the proper decision?O A. Fail to reject H. There is enough evidence at the 1% level of significance to reject the claim.O B. Reject Ho. There is not enough evidence at the 1% level of significance to reject the claim.O C. Fail to reject Ho. There is not enough evidence at the 1% level of significance to reject the claim.O D. Reject H. There is enough evidence at the 1% level of significance to reject the claim.Click to select vour answer(s).

x¯1=18,x¯2=20n1=30,n2=29σ1=3.3,σ2=1.5α=0.01

Answered: Test the claim about the difference…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Given:

${\bar{x}}_{1} = 18, {\bar{x}}_{2} = 20 n_{1} = 30, n_{2} = 29 σ_{1} = 3.3, σ_{2} = 1.5 α = 0.01$

Hypothesis testing:

$N u l l H y p o t h e s i s : H_{0} : μ_{1} = μ_{2} A l t e r n a t i v e H y p o t h e s i s : H_{a} : μ_{1} \neq μ_{2}$

Test statistic:

$z = \frac{{\bar{x}}_{1} - {\bar{x}}_{2}}{\sqrt{\frac{σ_{1}^{2}}{n_{1}} + \frac{σ_{2}^{2}}{n_{2}}}} = \frac{18 - 20}{\sqrt{\frac{3 . 3^{2}}{30} + \frac{1 . 5^{2}}{29}}} z = - 3.01$

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