Test Statistic (2 decimals): Give the P-value (4 decimals):

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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
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Part 2 and 3

Andre recenty found a die (the traditional, six-sided variety) at the
park. He took it home and rolled it 100 times and recorded the
results (found in the table below). Is this a 'fair die' or has it been
tampered with? Test at the a = 0.05 level of significance.
Which would be correct hypotheses for this test?
O Ho: The die is a fair die; H,: The die has been tampered with
Ho: P1 = P2; H1:P1 + P2
Ho: 41 = H2; H1 : µ1 # µ2
| Ho: The die has been tampered with; H:The die is a fair die
Roll count:
Rolled
Count
1
3.
3
5
6
86
Test Statistic (2 decimals):
Give the P-value (4 decimals):
Which is the correct result:
Do not Reject the Null Hypothesis
O Reject the Null Hypothesis
Which would be the appropriate conclusion?
There is not enough evidence to suggest that the die has been
tampered with.
O There is enough evidence to suggest that the die has been
tampered with.
Transcribed Image Text:Andre recenty found a die (the traditional, six-sided variety) at the park. He took it home and rolled it 100 times and recorded the results (found in the table below). Is this a 'fair die' or has it been tampered with? Test at the a = 0.05 level of significance. Which would be correct hypotheses for this test? O Ho: The die is a fair die; H,: The die has been tampered with Ho: P1 = P2; H1:P1 + P2 Ho: 41 = H2; H1 : µ1 # µ2 | Ho: The die has been tampered with; H:The die is a fair die Roll count: Rolled Count 1 3. 3 5 6 86 Test Statistic (2 decimals): Give the P-value (4 decimals): Which is the correct result: Do not Reject the Null Hypothesis O Reject the Null Hypothesis Which would be the appropriate conclusion? There is not enough evidence to suggest that the die has been tampered with. O There is enough evidence to suggest that the die has been tampered with.
Expert Solution
Step 1

Part 2.

Assume the equal proportion. The die is rolled 100 time. The proportion rolling 1 is 16.6667=16×100. For other values also having the sample expected value.

The expected value is,

Rolled Count Expected
1 0 16.6667
2 5 16.6667
3 3 16.6667
4 5 16.6667
5 1 16.6667
6 86 16.6667

The test statistic is,

χ2=Sum of Observed count-Expected count2Expected count=0-16.6667216.6667+5-16.6667216.6667+3-16.6667216.6667+5-16.6667216.6667+1-16.6667216.6667+0-16.6667216.6667=16.667+8.167+11.207+8.167+14.727+288.427=347.362347.36

Thus, the test statistic is 347.36.

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