For Tukey's HSD, how would you report your results?A Tukey's post hoc test (p < .05) revealed that the mean FIQ score for younger subjects (112.40) wassignificantly different than the mean FIQ scores for middle-age subjects (107.15) and older subjects (108.40).A Tukey's post hoc test (p < .05) revealed that the mean FIQ score for younger subjects (112.40) wassignificantly higher than the mean FIQ scores for middle-age subjects (107.15) and older subjects (108.40).A Tukey's post hoc test (p < .05) revealed that the mean FIQ score for younger subjects (109.08) wassignificantly lower than the mean FIQ score for middle-age subjects (112.40) but significantly higher than themean FIQ score for older subjects (107.15).A Tukey's post hoc test (p < .05) revealed that the mean FIQ scores for younger subjects (108.40) and oldersubjects (109.08) were not different, but both were significantly higher than the mean FIQ score for middle-age subjects (107.15).O A Tukey's post hoc test (p < .05) revealed that the mean FIQ scores for younger subjects (107.15) and middle-age subjects (108.40) were not different from one another, but both were significantly lower than the meanFIQ score for older subjects (112.40).None of the above OnewayPost Hoc TestsDescriptivesMultiple ComparisonsWAIS-R full scale IQDependent Variable: WAIS-R full scale IQ95% Confidence Interval forTukey HSDMeanMeanDifference (I-J)95% Confidence IntervalMeanStd. DeviationStd. ErrorLower BoundUpper BoundMinimumMaximum5-25 Years185107.1511.946.878105.41108.8877146(1) Subjects age in years(J) Subiects age in yearsStd. ErrorSig.Lower BoundUpper Bound26-59 Years380108.4012.840.659107.11109.70731505-25 Years26-59 Years-1.2571.115.497-3.871.3660-92 Years185112.4012.052.886110.65114.158114360-92 Years-5.2541.293<.001-8.29-2.22Total750109.0812.572.459108.18109.987315026-59 Years5-25 Years1.2571.115.497-1.363.8760-92 Years-3.997"1.115.001-6.61-1.3860-92 Years5-25 Years5.2541.293<.0012.228.29ANOVA26-59 Years3.9971.115.0011.386.61WAIS-R full scale IQ*. The mean difference is significant at the 0.05 level.Sum ofSquaresdfMean SquareFSig.Between Groups2905.50221452.7519.398<.001Homogeneous SubsetsWithin Groups115472.857747154.582Total118378.359749WAIS-R full scale IQTukey HSDa.bANOVA Effect SizesSubset for alpha = 0.05Subjects age in yearsN1295% Confidence IntervalPointEstimateLowerUpper5-25 Years185107.15WAIS-R full scale IQ Eta-squared108.4026-59 Years380.025.006.04960-92 Years185112.40Epsilon-squared.022.004.046Omega-squared Fixed-.022.004.046Sig..5341.000effectMeans for groups in homogeneous subsets are displayed.a. Uses Harmonic Mean Sample Size = 223.175.Omega-squaredRandom-effect.011.002.024b. The group sizes are unequal. The harmonic mean ofthe group sizes is used. Type I error levels are notguaranteed.a. Eta-squared and Epsilon-squared are estimated based on the fixed-effect model.

Given the output of One Way ANOVA and Post Hoc Tests. We have to write the results of Tukey’s HSD,

Answered: test (p<.05) revealed that the mean FIQ…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean consumption of water per household in a city was 1239 cubic feet per month Due to a water shortage because of a drought, the city council campaigned for water use conservation by households. A few months after the campaign was started, the mean consumption of water for a sample of 92 househoids was found to be 1157 cubic feet per month. The population standard deviation is given to be 251 cubic feet a. Find the p-value for the hypothesis test that the mean consumption of water per household has decreased due to the campaipn by the city council. Would you reject the null hypothesis at a = 0.025? Round your answer to four decimal places. pvalue =i We b. Make the test of part a using the critical-value approach and a = 0.025. Round your answer for z to two decimal places. Zoberved We We conclude that the mean consumption of water per household has due to the campaign by the city council.
If n=190 and ˆpp^ (p-hat) = 0.95, construct a 99% confidence interval.Give your answers to three decimals.
which one is right?
To compare customer satisfaction levels of two competing cable television companies, two samples are selected. The first sample selected from company one consist of 174 customers with mean 3.51 and standard deviation 0.51. And from company two 355 customers were selected with mean 3.24 and standard deviation 0.52 . From the above data can the researcher prove that the customers prefer first company at most the second company at α = 0.02 ? What the tabulated value value What the calculated value What the Decision
Calculate the Mean Squared Within Treatments (MS Within-Treatments ) value for an independent measures ANOVA with n = 12 observations in each of the three conditions, given SSBetween-Treatments =808 15 and SS Within-Treatments =680.85
A clinical trial is run to investigate the effectiveness of an experimental drug in reducing preterm delivery to a drug considered standard care and to placebo. Pregnant women are enrolled and randomly assigned to receive either the experimental drug, the standard drug or placebo. Women are followed through delivery and classified as delivering preterm (< 37 weeks) or not. The data are shown below. Is there a statistically significant difference in the proportions of women delivering preterm among the three treatment groups? Run the test at a 5% level of significance. Give each of the following 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value. Preterm Delivery Total Yes No Experimental Drug Standard Drug Placebo Total 33 40 32 45 13 18 17 35 37 83 120
3) Last year, the mean running time for a certain type of flash light battery was 8.5 hours. This year, the manufacturer has introduced a change in the production method which he hopes will change the mean running time. A random sample of 40 of the new light bulbs was obtained and the mean running time was found to be 8.7 hours. Do the data provide sufficient evidence to conclude that the mean running time of the new light bulbs is different from last year's mean of 8.5 hours? Perform the appropriate hypothesis test using a significance level of 0.05. Assume that standard deviation of running time of all new light bulb batteries of this type is 0.5 hours.
A marketing research company is estimating which of two soft drinks college students prefer. A random sample of 110 college students produced the following 95% confidence interval for the proportion of college students who prefer drink A: (0.228, 0.603). Identify the point estimate (p^p^) for estimating the true proportion of college students who prefer that drink. Round to the nearest thousandth.
The most common intelligence quotient (IQ) scale is Normally distributed with a mean of \\( 100 \\) and a standard deviation of \\( 15 . \\) Many school districts across the country seek to identify "gifted and talented" children for special enrichment programs. Typically, these children must have IQ scores in the top \\( 5 \\)%. What is the minimum score to qualify a child for these programs?
The mean and standard deviation of system blood pressure of 200 employees in a factory were 127mmhg and 13 mmHg respectively. Calculate and interprete the 95% confidence interval of systolic blood pressure of the employees
The mean age when smokers first start is 13 years old with a population standard deviation of 1.8 years. A researcher thinks that smoking age has significantly changed since the invention of ENDS-electronic nicotine delivery systems. A survey of smokers of this generation was done to see if the mean age has changed. The sample of 35 smokers found that their mean starting age was 12.3 years old. Do the data support the- claim at the 5% significance level? What are the correct hypotheses? Ho: Select an answer e years H1: Select an answer e years Based on the hypotheses, find the following: Test Statistic z = (Round to 4 decimal places.) Critical Values = = (Round to 2 decimal places.) Based on the above we choose to Select an answer O that the mean age smokers The correct summary would be: Select an answer first start is different than 13.
The Census Bureau reports that 82% of Americans over the age of 25 are high school graduates. A survey of randomly selected residents of certain county included 1100 who were over the age of 25, and 871 of them were high school graduates, (a) Find the mean and standard deviation for the number of high school graduates in groups of 1100 Americans over the age of 25. Mean = %3D Standard deviation = (b) Is that county result of 871 unusually high, or low, or neither? (Enter HIGH or LOW or NEITHER) Give your answers exactly, or to at least 4 decimal places.

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