Test at the 0.05 level the claim that the type of crime relates to whether the criminal is a stranger. The null hypothesis (H_0) is Select one: O a. p_{criminal was a stranger} = p_{crimial was an acquaintance or relative} O b. p_{homicide} = p_{robbery} = p_{assault} =1/3 O c. The type of crime is dependent on whether the criminal is a stranger O d. None of the other answers in necessary true. e. The type of crime is independent of whether the criminal is a stranger

Test at the 0.05 level the claim that the type of crime relates to whether the criminal is a stranger. The null hypothesis (H_0) is Select one: O a. p_{criminal was a stranger} = p_{crimial was an acquaintance or relative} O b. p_{homicide} = p_{robbery} = p_{assault} =1/3 O c. The type of crime is dependent on whether the criminal is a stranger O d. None of the other answers in necessary true. e. The type of crime is independent of whether the criminal is a stranger

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A teacher claims that over 13% of maths students are married, in the survey at the beginning of semester, 55 students answered the question about their marital satatus. 13 of them said they were married. Calculate the test statistic Z } } 1 1 1 1 02-
5. A psychologist want to determine effect from consumption alcohol to ability type from group secretary . Two factor considered , namely : the number of consumption alcohol (0, 1, and 2 ounces ) and type articles ( technical , non- technical ). group of 12 secretaries who have ability similar in type by random chosen with level / level of consumption and type article . Every secretary instructed_ for type one sheet page ( technical or non-technical ). Amount error type created by each_ Secretary noted with results as follows . Type of manuscript Alcoholic Consumption (ounces) Technical Nontechnical 5 3 2 1 12 3 14 6 18 10 21 7 At level significance of 0.01, do the test: a) Is there is effect because level consumption alcohol ? b) Is there is effect because type articles ?? c) Is there is interaction Among consumption alcohol and types article ?
The following data are the daily number of minutes of smartphone use for a random sample of 8students at your institution: 117, 156, 89, 72, 116, 125, 101, 100.(You may use t(df=7, 0.05) = -1.895) (a) Test the null hypothesis according to which the true mean is greater or equal to 100 minagainst the alternative that it is less than 100. Use a significance level of 5% (state the test statistic and the conclusion).
A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.4 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. i Click the icon to view the display from technology. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? O A. Ho: μ=2.4 miles O B. Ho: μ=2.4 miles H₁: μ#2.4 miles H₁: μ 2.4 miles Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is greater than 2.4 miles evidence to support the claim that the mean tornado length is
85% of all restaurants fail after one year. Is that number different_for Chinese restaurants? Out of a random selection of 200 new Chinese restaurants, 175 had failed after one year. Use a 0.05 significance level to test your hypothesis. What is the Z obr? (round to the nearest whole number)
When conducting an ANOVA on sbp and genhelth, the p-value is 0.008. Therefore we conclude Group of answer choices reject the null hypothesis at 1% level, mean sbp different for at least one category of genhelth reject the null hypothesis at 5% level, mean sbp different for all categories of genhelth reject the null hypothesis at 1% level, mean sbp different for all categories of genhelth no evidence to reject the null hypothesis of equal means
For a Lower one-tailed hypothesis test with a sample size of 18 at a = .10, the critical value for the decision would be: O 2.11 O -2.11 O -1.740 O 1.333 O none of these < Previous Next »
in a one-tail hypothesis test where H_{0} is only rejected in the upper tail, the p-value 0.1029 and Z STAT =+1.27 what is the statistical decision if the null hypothesis is tested at the 0.08 level of significance? What is the statistical decision? H_{0} Since the p-value is (Type an integer or a decimal. Do not round.
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Clark Barr makes a claim that 10% of all students who take statistics drop out. Rosetta Stone decidesto test his claim, since she believes that the dropout rate is greater than 10%. Rosetta uses a randomsample of 15e`0 students currently enrolled in a statistics course. In her sample, Rosetta finds that of the150 students, 22 dropped out. Test to determine the validity of Clark Barr’s claim at the 0.01 significancelevel. (Show all seven steps.)
In a recent court case it was found that during a period of 11 years 851 people were selected for grand jury duty and 40% of them were from the same ethnicity. Among the people eligible for grand jury duty, 80% were of this ethnicity Use a 0.01 significance level to test the claim that the selection process is based against allowing this ethnicity to sit on the grand jury. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What is the test statistic? (Round to two decimal places as needed.)
Consider trying to predict the life expectancy of citizens in a country based on the birth rate (per 1000 people) in that country. Here is a scatterplot of the data from a random sample of 50 countries. > ggplot (SampCountries, aes (BirthRate, LifeExpectancy)) + geom_point (color = "darkred")+ labs (title = "Life Expectancy by Birth Rate") + Life Expectancy by Birth Rate 80 - 70 - 10 20 30 40 BirthRate Here is (some of) the R output for the linear model for this data. > LifeBirth.lm summary (LifeBirth. lm) Call: Im (formula = LifeExpectancy BirthRate, data = SampCountries) Residuals: Min 10 Median 30 Маx -7.0592 -2.3047 0.9123 2.5019 5.8358 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 85.26295 1.03301 82.54 BirthRate -0.63291 0.04492 -14.09 Residual standard error: 3.424 on 48 degrees of freedom Multiple R-squared: 0.8053, Adjusted R-squared: 0.8012 F-statistic: 198.5 on 1 and 48 DF, p-value: < 2.2e-16 LifeExpectancy