template int ternary_search(const ArrayLike& array, const T& value, int low, int high) { // Base case: if (high return -1; low) // General case: int one_third = low + (high - low) / 3; int two_thirds if (array[one_third] > value) { // if we should recurse on the 1st third = low + 2 * (high Low) / 3;
template int ternary_search(const ArrayLike& array, const T& value, int low, int high) { // Base case: if (high return -1; low) // General case: int one_third = low + (high - low) / 3; int two_thirds if (array[one_third] > value) { // if we should recurse on the 1st third = low + 2 * (high Low) / 3;
Programming Logic & Design Comprehensive
9th Edition
ISBN:9781337669405
Author:FARRELL
Publisher:FARRELL
Chapter6: Arrays
Section: Chapter Questions
Problem 12PE
Related questions
Question
Using recurrence relations, solve the big-O of the following. Assume ArrayLike has the same big-O as an array and that comparing T objects to each other is O(1). Show work.
![template <typename ArrayLike, typename T>
int ternary_search(const ArrayLike& array, const T& value, int low, int high) {
// Base case:
if (high <= low)
return -1;
// General case:
int one_third
int two_thirds =
if (array[one_third] > value) { // if we should recurse on the 1st third
return ternary_search(array, value, low, one_third);
} else if (array[one_third]
return one_third;
} else if (array[two_thirds] > value) { // if we should recurse on 2nd third
return ternary_search(array, value, one_third + 1, two_thirds);
} else if (array[two_thirds]
return two_thirds;
} else { // else we should recurse on the last third
return ternary_search(array, value, two_thirds + 1, high);
}
}
low + (high - low) / 3;
= low + 2 * (high - low) / 3;
value) { // if value is at the 1st third
==
value) { // if value is at the 2nd third
==](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F47bcd2e2-fd09-4d16-8209-9beee0b05010%2F1c44cb32-2fb9-4353-b538-2b972be53c06%2Fuw6pvk_processed.png&w=3840&q=75)
Transcribed Image Text:template <typename ArrayLike, typename T>
int ternary_search(const ArrayLike& array, const T& value, int low, int high) {
// Base case:
if (high <= low)
return -1;
// General case:
int one_third
int two_thirds =
if (array[one_third] > value) { // if we should recurse on the 1st third
return ternary_search(array, value, low, one_third);
} else if (array[one_third]
return one_third;
} else if (array[two_thirds] > value) { // if we should recurse on 2nd third
return ternary_search(array, value, one_third + 1, two_thirds);
} else if (array[two_thirds]
return two_thirds;
} else { // else we should recurse on the last third
return ternary_search(array, value, two_thirds + 1, high);
}
}
low + (high - low) / 3;
= low + 2 * (high - low) / 3;
value) { // if value is at the 1st third
==
value) { // if value is at the 2nd third
==
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