Technology Results Pooled proportion: 0.40 Test statistic, z: 13.2930 Critical z: 1.2816 P-value: 0.0000 80% Confidence interval: 0.5240667
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- chebentenTwo hundred fish caught in Cayuga Lake had a mean length of 13.4 inches. The population standard deviation is 3.2 inches. (Give your answer correct to two decimal places.) (a) Find the 90% confidence interval for the population mean length. Lower Limit Upper Limit (b) Find the 98% confidence interval for the population mean length. Lower Limit Upper LimitQ16 Use t distribution table and normal standard distribution table
- 3) Estimating the Mean: Unknown Variance a) A student is working on his science fair project concerning the average height of a certain native plant, which he believes is normally distributed. He finds 25 mature plants and measures their heights, and determines the average height to be 10.2 cm (s = 1.2 cm). Construct a 96% confidence interval on the mean height of the plants. .<μ<.B Question 2 of 12 (a) 95% confidence interval for μ₁ Conclusion: Hypotheses for a statistical test are given, followed by several possible confidence intervals for different samples. In each case, use the confidence interval to state a conclusion of the test for that sample and give the significance level used. In addition, in each case for which the results are significant, state which group (1 or 2) has the larger mean. Significance < Reject Do not reject Group with the larger mean: Conclusion: Significance level: Ho - (b) 99% confidence interval for μ₁ −μ₂: -2.3 to 5.3 Group with the larger mean: Hypotheses: Ho: M₁ = M₂ Vs Ha: M₁ M₂ ✓ Ho -M₂: 0.11 to 0.41 -/1 = :Hip surgery: In a sample of 118 hip surgeries of a certain type, the average surgery time was 135.9 minutes with a standard deviation of 22.1 minutes. Part: 0 / 2 0 of 2 Parts Complete Part 1 of 2 (a) Construct a 99% confidence interval for the mean surgery time for this procedure. Round your answers to one decimal place. A 99% confidence interval for the mean surgery time for this procedure is <<μ .
- Urgentmean(rsession$Years.of.secondary.schooling) [1] 4.255708 sd(rsession$Years.of.secondary.schooling) [1] 1.226018 Using the statistics calculated above, construct a 95% confidence interval for the mean number of years of secondary education for employed individuals in this country and briefly interpret this interval. Sample size = 219Find the critical value Za that corresponds to the confidence level 84% Answer: Probability ( if use for Excel or TI 84 )/ area ( if using table ) ( three decimal place) Z a = ( two decimal places) ing
- One Sample T-test and Confidence Interval The average monthly cell phone bill was reported last year to be $53.88 by the U.S. Wireless Industry. Random sampling of a large cell phone company found the current monthly cell phone charges (in dollars) in the table on the left. At the 0.05 level of significance, can it be concluded that the average cell phone bill has increased? Also find an 85% confidence interval estimate of the current mean monthly cell phone bill. Cell Phone Bills 55.83 60.47 58.60 49.88 52.45 51.29 32.98 49.20 70.42 50.02 75.04 41.88 35.00 61.58 58.99 61.25 62.00 80.21 73.60 71.52 42.80 38.65 49.54 61.88 46.30 74.10 48.63 63.45 44.43 36.77 71.96 77.79 42.13 63.24 67.56 74.44 31.77 76.91 73.04 79.92 67.10 78.13 37.95 45.60 68.88 54.47 43.47 54.57 76.12 80.45 38.08 57.21 54.28 a. State the random variable and the parameter in words. b. State the null and…monitor the percentage fat in hot dogs produced at a food processing plant a quality control technician randomly selects 15 hot dogs and measures the percentage fat of each. The sample data yield mean (xbar) 24.1 percent and standard deviation 0.9 percent. On the assumption that the fat content has a normal distribution a 95% confidence interval for the true mean percentage fat for all hot dogs currently being produced is about.Drill lifetime: A sample of 50 drills had a mean lifetime of 12.88 holes drilled when drilling a low-carbon steel. Assume the population standard deviation is 6.31. Part: 0 / 3 Part 1 of 3 (a) Construct a 95% confidence interval for the mean lifetime of this type of drill. Use tables or technology. Round your answers to at least two decimal places. The confidence interval is NOV 20 ... MacBook Air DII 80 888 F8 F9 F10 F5 F6 F7 F2 F3 F4 & @ %23 24 6. 7 * CO