Task 4 [Computing Pl via Leibniz series] This task is to help you use for-loops for mathematical expressions in code. It is an irrational number that means it cannot be expressed as a fraction. Ever wonder how we compute ? One of the pioneers of the mechanical calculator, Gottfried Wilhelm von Leibniz, proved that could be expressed with the following infinite series: 1 1 1 1 1 1 1 + + 35-7 1 1 1 + 9 11 13 15 17 19 TT 4 Notice the alternating plus/minus sign in the series. We call each of the fractions in the series a "term." To compute π requires the summing of an infinite number of terms; however, in practice, this is not possible. Instead, we can only approximate the true value using a finite number of terms. Using the Leibniz formula, the more terms we compute in the series, the more accurate our calculation of π. Your task is to compute π up to a user-specified number of terms (i.e., up to M terms). Don't get scared of math, it is easy once you understand it. The Σ (sigma) symbol is a mathematician's way of We can rewrite Leibniz's series in a more compact form as

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Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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Task 4 [Computing Pl via Leibniz series]
This task is to help you use for-loops for mathematical expressions in code.
It is an irrational number - that means it cannot be expressed as a fraction. Ever wonder how we compute ?
One of the pioneers of the mechanical calculator, Gottfried Wilhelm von Leibniz, proved that could be
expressed with the following infinite series:
1-
1 1 1
5 7 9 11 13 15 17 19
1 1 1 1 1 1
+
+
3
We can rewrite Leibniz's series in a more compact form as
follows:
π = 4 x
Notice the alternating plus/minus sign in the series. We call each of the fractions in the series a "term." To
compute requires the summing of an infinite number of terms; however, in practice, this is not possible.
Instead, we can only approximate the true value using a finite number of terms. Using the Leibniz formula, the
more terms we compute in the series, the more accurate our calculation of . Your task is to compute π up
to a user-specified number of terms (i.e., up to M terms).
Don't get scared of math, it is easy once you understand it.
The Σ (sigma) symbol is a mathematician's way of
expressing a "for loop" for summing up terms. This
symbol means the following:
sum=0
for n
M
Σ
n=0
(-1)"
2n + 1
Your task should work as follows:
(1) Ask the user for the number of terms, M.
(2) Compute pi based on Leibniz formulation.
(3) At each iteration of your for-loop, print out the result
(i.e., your current sum x 4)
Print your results with precision 12.
Compare your result with 3.14159265359.
See example output below:
our pi= 3.33968253968
real pi= 3.14159265359
n=5
---- Task 4: Compute PI
Input number of terms, M: 10
n=0
adding fraction: 1/1
our pi4.00000000000
real pi= 3.14159265359
n=1
adding fraction: -1/3
our pi 2.66666666667
real pi= 3.14159265359
n=2
adding fraction: 1/5
our pi= 3.46666666667
real pi= 3.14159265359
n=3
our pi 2.89523809524
real pi= 3.14159265359
n=4
adding fraction: -1/7
adding fraction: 1/9
adding fraction: -1/11
our pi 2.97604617605
real pi= 3.14159265359
n=6
adding fraction: 1/13
our pi= 3.28373848374
real pi= 3.14159265359
+ ...=
sum
range (0,M+1):
sum + [term]
Here, [term] is the result of the expression in
blue, evaluated using the current value of n in the
for loop. For example, if M=2, we have:
TT
4
n=0, we have
n=1, we have
(-1)⁰
2*0+1
(-1)¹
2+1
1
2*1+1
(-1)²
n=2, we have
2*2+1
4+1
(Look familiar? This is Leibniz's series.)
3
- +
1
5
Transcribed Image Text:Task 4 [Computing Pl via Leibniz series] This task is to help you use for-loops for mathematical expressions in code. It is an irrational number - that means it cannot be expressed as a fraction. Ever wonder how we compute ? One of the pioneers of the mechanical calculator, Gottfried Wilhelm von Leibniz, proved that could be expressed with the following infinite series: 1- 1 1 1 5 7 9 11 13 15 17 19 1 1 1 1 1 1 + + 3 We can rewrite Leibniz's series in a more compact form as follows: π = 4 x Notice the alternating plus/minus sign in the series. We call each of the fractions in the series a "term." To compute requires the summing of an infinite number of terms; however, in practice, this is not possible. Instead, we can only approximate the true value using a finite number of terms. Using the Leibniz formula, the more terms we compute in the series, the more accurate our calculation of . Your task is to compute π up to a user-specified number of terms (i.e., up to M terms). Don't get scared of math, it is easy once you understand it. The Σ (sigma) symbol is a mathematician's way of expressing a "for loop" for summing up terms. This symbol means the following: sum=0 for n M Σ n=0 (-1)" 2n + 1 Your task should work as follows: (1) Ask the user for the number of terms, M. (2) Compute pi based on Leibniz formulation. (3) At each iteration of your for-loop, print out the result (i.e., your current sum x 4) Print your results with precision 12. Compare your result with 3.14159265359. See example output below: our pi= 3.33968253968 real pi= 3.14159265359 n=5 ---- Task 4: Compute PI Input number of terms, M: 10 n=0 adding fraction: 1/1 our pi4.00000000000 real pi= 3.14159265359 n=1 adding fraction: -1/3 our pi 2.66666666667 real pi= 3.14159265359 n=2 adding fraction: 1/5 our pi= 3.46666666667 real pi= 3.14159265359 n=3 our pi 2.89523809524 real pi= 3.14159265359 n=4 adding fraction: -1/7 adding fraction: 1/9 adding fraction: -1/11 our pi 2.97604617605 real pi= 3.14159265359 n=6 adding fraction: 1/13 our pi= 3.28373848374 real pi= 3.14159265359 + ...= sum range (0,M+1): sum + [term] Here, [term] is the result of the expression in blue, evaluated using the current value of n in the for loop. For example, if M=2, we have: TT 4 n=0, we have n=1, we have (-1)⁰ 2*0+1 (-1)¹ 2+1 1 2*1+1 (-1)² n=2, we have 2*2+1 4+1 (Look familiar? This is Leibniz's series.) 3 - + 1 5
n=7
adding fraction: -1/15
3.01707181707
= 3.14159265359
.. adding fraction: 1/17
= 3.25236593472
= 3.14159265359
our pi
real pi
n=8
=
our pi
real pi
n=9 ... adding fraction: -1/19
our pi
real pi
3.04183961893
= 3.14159265359
=
n=10 ... adding fraction: 1/21
our pi
= 3.23231580941
real pi = 3.14159265359
Try this for M=10000. Remember, before computers, a person would have computed this by hand.
Isaac Newton (not using the method above) computed up to a precision of 16 decimal places in 1665.
The current record holder is Emma Haruka Iwao. She has estimated with over 31 trillion digits (and not by
hand!)
Transcribed Image Text:n=7 adding fraction: -1/15 3.01707181707 = 3.14159265359 .. adding fraction: 1/17 = 3.25236593472 = 3.14159265359 our pi real pi n=8 = our pi real pi n=9 ... adding fraction: -1/19 our pi real pi 3.04183961893 = 3.14159265359 = n=10 ... adding fraction: 1/21 our pi = 3.23231580941 real pi = 3.14159265359 Try this for M=10000. Remember, before computers, a person would have computed this by hand. Isaac Newton (not using the method above) computed up to a precision of 16 decimal places in 1665. The current record holder is Emma Haruka Iwao. She has estimated with over 31 trillion digits (and not by hand!)
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