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Tanks A and B containing oil and glycerin of sp.gr. 0.78 and 1.25 respectively are connected by a differential gage. The mercury (sp.gr. = 13.6) in the gage is at elev. 1.60m on the A side and at 1.10m on the B side. If the elevation surface of glycerin int the tank B is 21.10m, at what elevation is the surface of oil in tank A? Elev = ? oil -ELev 21.10m S:0.78 GLycerin S- 1.25 -Eler1.60m Elev 1.10m Hg (13.6)

Tanks A and B containing oil and glycerin of sp.gr. 0.78 and 1.25 respectively are connected by a differential gage. The mercury (sp.gr. = 13.6) in the gage is at elev. 1.60m on the A side and at 1.10m on the B side. If the elevation surface of glycerin int the tank B is 21.10m, at what elevation is the surface of oil in tank A? Elev = ? oil -ELev 21.10m S:0.78 GLycerin S- 1.25 -Eler1.60m Elev 1.10m Hg (13.6)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Tanks A and B containing oil and glycerin of sp.gr. 0.78 and 1.25 respectively are connected by a differential gage. The mercury (sp.gr. = 13.6) in the gage is at elev. 1.60m on the A side and at 1.10m on the B side. If the elevation surface of glycerin int the tank B is 21.10m, at what elevation is the surface of oil in tank A? Elev = ? oil -ELev 21.10m S= 0.78 G Lycerin S= 1.25 -ELer l.60m Elev 1.10m Hg (13.6)
Transcribed Image Text:Tanks A and B containing oil and glycerin of sp.gr. 0.78 and 1.25 respectively are connected by a differential gage. The mercury (sp.gr. = 13.6) in the gage is at elev. 1.60m on the A side and at 1.10m on the B side. If the elevation surface of glycerin int the tank B is 21.10m, at what elevation is the surface of oil in tank A? Elev = ? oil -ELev 21.10m S= 0.78 G Lycerin S= 1.25 -ELer l.60m Elev 1.10m Hg (13.6)
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