tandard deviation for gnΣf X)-n(n-1mb: sran4s). A survey of 240 men found that 144 gamble. Another survey of 220 womenfound that 110 gamble. Let p₁ and p2 be the proportions of men and women who gamble,respectively.(a) Find the point estimate of p₁ - p2 and its maximum error E using a =(b) Construct a 95% confidence interval for pi - p2.(c) Test at a == 0.05.€0.05 if the proportion of men who gambling is higher than that ofwomen (p1-P2 > 0).(d) Find the P-value of this test.(e) Check if the assumptions for this test are satisfied.

Step 1: Calculate Point Estimate of p1−p2The sample proportions are: p^1= Number of men who…

Answered: tandard deviation for g nΣf X)- n(n-1…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A random sample of 24 items is drawn from a population whose standard deviation is unknown. The sample mean is 3D870 and the sample standard deviation is s= 25. Use Appendix D to find the values of Student's t. (a) Construct an interval estimate of u with 98% confidence. (Round your answers to 3 decimal places.) The 98% confidence interval is from to (b) Construct an interval estimate of u with 98% confidence, assuming that s= 50. (Round your answers to 3 decimal places The 98% confidence interval is from to (c) Construct an interval estimate of ụ with 98% confidence, assuming that s = 100. (Round your answers to 3 decimal places.) The 98% confidence interval is from to (d) Describe how the confidence interval changes as s increases. O The interval stays the same as s increases. on
The number of needed repairs while under warranty for a Sure Cut lawnmower has a population distribution as shown in the probability histogram below. The population mean is also given. Population 0.6 - 0.5- 0.4- population mean: u=1.15 0.3- 0.2- Number of repairs Probability
If n=16, ¯xx¯(x-bar)=35, and s=17, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place. I used the formula 35-NORM.INV(1-2.0/2,0,1)*((17)/SQRT(16)) for the lower and the same but with a plus sign for the upper, I got it wrong and dont understand why. We have to use Excel so please explain what excel formula to use.
Please answer this question for me because i do not understand how to work it.
(a) A random sample of n = 36 students who took an examination yields the confidence interval (73 , 74), for the population mean u. The standard deviation o = 1.875. Find the confidence coefficient 100(1 – a)% of this interval. (b) Assume o = 2. How many students should be selected in order to be 98% confident that the margin of error E = +0.6 ?
A marketing researcher is hired by a corporation to conduct a study and estimate the population mean for the attribute of interest using a 98% confidence interval with a maximum error of 5. It will cost the researcher $15 per sample to conduct the study and the researcher has been given a budget of $750 to conduct the study. Based on prior studies the researcher can estimate the standard deviation using, σ≈16�≈16. Step 1 of 3: Calculate the minimum sample size needed for this study. Round your answer up to the nearest whole number.
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16:03 d 12.0 VoD :4G KB/S LTEB l 41% 4 A sample of 30 students from a Faculty has been obtained to estimate the average grade of the students' records in the Faculty. It is known from other courses that the standard deviation of the scores in said Faculty is 1.05 points. The mean of the sample was 3.5. Construct a 90% Confidence Interval for the average of the students' grades.
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