Take this program, which is a variation on the first program in this lab, but uses integer arrays instead of C-strings: #include int main(void) { int intPtr[] {0x1234, 0x5678, 0x9abc}; int length = 3; int* currPtr = intPtr; while (currPtr - intPtr < length) { printf ("%p: ", currptr); printf("0x%02x\n", *currPtr); currPtr++; } return 0; Comment each line of code within main(), except for the return 0. Emphasize the differences between this code and the C-string version of the code. /* intAndFloat.c * Using printf to display an integer and a float. * 2017-09-29: Bob Plantz */ #include int main(void) int anInt= 19088743; float afloat= 19088.743; printf("The integer is %d and the float is %f\n", anInt, aFloat); return 0; * first program * Listing 2.9.1. in-context

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Please help!

Please take a look at the code I have provided as a attachment to this question. 

Please comment each line of code of the differences between program 1 and 2.

  • What happens when you subtract one pointer from another? Is it subtracting the two addresses, or something else? How do you know?
  • What happens when you increment a pointer?
  • Compare and contrast how C-strings are laid out in memory compared to arrays of integers. What's one similarity and one difference?
  • Show how the individual bytes of this integer array are laid out in memory. 

 

Thanks!

Take this program, which is a variation on the first program in this lab,
but uses integer arrays instead of C-strings:
# include <stdio.h>
int main(void) {
int intPtr [] = {0x1234, 0x5678, 0x9abc};
int length = 3;
int* currPtr = intPtr;
while (currPtr - intPtr <length) {
printf("%p: ", currptr);
printf("0x%02x\n", *currptr);
currPtr++;
}
return 0;
}
Comment each line of code within main(), except for the return 0.
Emphasize the differences between this code and the C-string version of
the code.
/* intAndFloat.c
* Using printf to display an integer and a float.
* 2017-09-29: Bob Plantz
*/
#include <stdio.h>
int main(void)
{
int anInt = 19088743;
float aFloat= 19088.743;
printf("The integer is %d and the float is %f\n", anInt, aFloat);
return 0;
* first program *
Listing 2.9.1.
in-context
Transcribed Image Text:Take this program, which is a variation on the first program in this lab, but uses integer arrays instead of C-strings: # include <stdio.h> int main(void) { int intPtr [] = {0x1234, 0x5678, 0x9abc}; int length = 3; int* currPtr = intPtr; while (currPtr - intPtr <length) { printf("%p: ", currptr); printf("0x%02x\n", *currptr); currPtr++; } return 0; } Comment each line of code within main(), except for the return 0. Emphasize the differences between this code and the C-string version of the code. /* intAndFloat.c * Using printf to display an integer and a float. * 2017-09-29: Bob Plantz */ #include <stdio.h> int main(void) { int anInt = 19088743; float aFloat= 19088.743; printf("The integer is %d and the float is %f\n", anInt, aFloat); return 0; * first program * Listing 2.9.1. in-context
Expert Solution
Step 1: Algorithm of the program:

Algorithm:

  1. Initialize an integer variable, length, with the value 3.
  2. Initialize an integer variable, length, with the value 3.
  3. Create an integer pointer, currPtr, and set it to point to the first element of intArr.
  4. Start a loop that continues as long as currPtr is within the bounds of intArr.
  5. Print the memory address pointed to by currPtr.
  6. Print the hexadecimal value at the address pointed to by currPtr.
  7. Move currPtr to point to the next integer in the array.
  8. End the loop when currPtr goes beyond the bounds of intArr.
  9. Terminate the program by returning 0.
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