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+Tabulated Data and Result, Modulus of Rupture Sample No. L (mm) b (mm) h (mm) 1 730 50 50 2 730 50 50 3 730 50 50 Tabulated Data and Result, Apparent Modulus of Elasticity Sample No. L (mm) b (mm) h (mm) 1 730 50 50 2 730 50 50 3 730 50 50 Incremental P (N) 200 200 200 Pmax (N) 2670 2585 2700 Incremental A (mm) 2 3 3.5 MR (MPa) E (MPa)

+Tabulated Data and Result, Modulus of Rupture Sample No. L (mm) b (mm) h (mm) 1 730 50 50 2 730 50 50 3 730 50 50 Tabulated Data and Result, Apparent Modulus of Elasticity Sample No. L (mm) b (mm) h (mm) 1 730 50 50 2 730 50 50 3 730 50 50 Incremental P (N) 200 200 200 Pmax (N) 2670 2585 2700 Incremental A (mm) 2 3 3.5 MR (MPa) E (MPa)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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+Tabulated Data and Result, Modulus of Rupture Sample No. L (mm) b (mm) h (mm) 1 730 50 50 2 730 50 50 3 730 50 50 Tabulated Data and Result, Apparent Modulus of Elasticity Sample No. L (mm) b (mm) h (mm) 1 730 50 50 2 730 50 50 3 730 50 50 Incremental P (N) 200 200 200 Pmax (N) 2670 2585 2700 Incremental A (mm) 2 3 3.5 MR (MPa) E (MPa)
Transcribed Image Text:+Tabulated Data and Result, Modulus of Rupture Sample No. L (mm) b (mm) h (mm) 1 730 50 50 2 730 50 50 3 730 50 50 Tabulated Data and Result, Apparent Modulus of Elasticity Sample No. L (mm) b (mm) h (mm) 1 730 50 50 2 730 50 50 3 730 50 50 Incremental P (N) 200 200 200 Pmax (N) 2670 2585 2700 Incremental A (mm) 2 3 3.5 MR (MPa) E (MPa)
Calculation: Modulus of Rupture: 3PmaxL MR = 2bh² Apparent Modulus of Elasticity: PL³ E = (4) 4bh³ Pmax and L = maximum load and span of the beam b and h = width and height of the cross-section P = increment of applied load below proportional limit A = increment of deflection of beam's neutral axis measured at midspan over distance L and corresponding load P Note: The weight of the beam is not included in the above calculation. Where:
Transcribed Image Text:Calculation: Modulus of Rupture: 3PmaxL MR = 2bh² Apparent Modulus of Elasticity: PL³ E = (4) 4bh³ Pmax and L = maximum load and span of the beam b and h = width and height of the cross-section P = increment of applied load below proportional limit A = increment of deflection of beam's neutral axis measured at midspan over distance L and corresponding load P Note: The weight of the beam is not included in the above calculation. Where:
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