How do i find the specific heat of Zinc whenmass: 20.422gvolume of water: 50.5initial temperature of metal: 93.1 Cinitial temperature of water: 19.5 Cfinal temperature after mixing water and metal: 21.9 C Table 5. Specific Heat of a MetalSample 1Identity of metalZinc[1] Mass of metal (g)20.411[2] Volume of DI water (mL)50.550.5Mass of DI water (g)[3] Tinitial metal (°C)93.1[4] Tinitial water (°C)19.5[5] Trinal of mixture after addition ofmetal (°C)21.9Specific heat of metal Cmetal (cal/g-°C)

Given that, Mass of metal mM = 20.411 g Volume of water VW = 50.5 mL Mass of water mW = 50.5 g Initial Temperature of Metal TM = 93.1oC Initial Temperature of Water TW = 19.5oC Final Temperature of the mixture of water and metal Tf = 21.9oC It is required to calculate the specific heat of metalSpecific heat of the water CWater = 1 Calg.Co By energy balance: Heat lost by metal = Heat gained by the water mMCMetalTM - Tf = mWCWaterTf - TWCMetal = mWCWaterTf - TWmMTM - TfCMetal = 50.5 g × 1 Calg.Co × 21.9 - 19.5Co20.411 g × 93.1 - 21.9CMetal = 0.0834 Calg.CoAnswer: Specific heat of metal CMetal = 0.0834 Calg.Co

Answered: Table 5. Specific Heat of a Metal…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

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How do i find the specific heat of Zinc when

mass: 20.422g

volume of water: 50.5

initial temperature of metal: 93.1 C

initial temperature of water: 19.5 C

final temperature after mixing water and metal: 21.9 C

Table 5. Specific Heat of a Metal
Sample 1
Identity of metal
Zinc
[1] Mass of metal (g)
20.411
[2] Volume of DI water (mL)
50.5
50.5
Mass of DI water (g)
[3] Tinitial metal (°C)
93.1
[4] Tinitial water (°C)
19.5
[5] Trinal of mixture after addition of
metal (°C)
21.9
Specific heat of metal Cmetal (cal/g-°C)

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