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Table 5: Data for Activity 3. Material Critical Angle, e sin e Refractive index, n Water 87 0.999 1.0014 Glass 89 0.991 1.5002 Mystery Material A 87 0.999 1.00 Mystery Material B 89 0.991 1.00 Q14. Complete the following statement. The index of refraction of the lower medium, which is air, is n _1.00027

Table 5: Data for Activity 3. Material Critical Angle, e sin e Refractive index, n Water 87 0.999 1.0014 Glass 89 0.991 1.5002 Mystery Material A 87 0.999 1.00 Mystery Material B 89 0.991 1.00 Q14. Complete the following statement. The index of refraction of the lower medium, which is air, is n _1.00027

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Activity 3 The Critical Angle Retum to your simulation and set up the simulation so that it looks like the screenshot in Figure 5. Change the upper material to water, and change the bottom material to be air • Choose Water for the upper material and Air for the lower material Meri do nde of etacton 100 PŘET = Bending Light Figure 5: Set up for Activity 3. 1. Start with the incident angle e = 30°. 2. Gradually increase the angle of incidence until 0, = 40°. Read off and record the angles of reflection and refraction below. Angle of reflection = 40 Angle of refraction 58 3. Continue to slowly increase the angle of incidence until the angle of refraction is as close to 90° as you can get it, as shown in the image to the right. (At this point, if you slightly increase the angle of incidence the refracted ray will disappear!) 60 The angle of incidence at which the angle of refraction is 90° is called the "critical angle, 6.", stated mathematically, when e: = 90°, 6, = 30 Record the critical angle for the water-to-air interface here:
Transcribed Image Text:Activity 3 The Critical Angle Retum to your simulation and set up the simulation so that it looks like the screenshot in Figure 5. Change the upper material to water, and change the bottom material to be air • Choose Water for the upper material and Air for the lower material Meri do nde of etacton 100 PŘET = Bending Light Figure 5: Set up for Activity 3. 1. Start with the incident angle e = 30°. 2. Gradually increase the angle of incidence until 0, = 40°. Read off and record the angles of reflection and refraction below. Angle of reflection = 40 Angle of refraction 58 3. Continue to slowly increase the angle of incidence until the angle of refraction is as close to 90° as you can get it, as shown in the image to the right. (At this point, if you slightly increase the angle of incidence the refracted ray will disappear!) 60 The angle of incidence at which the angle of refraction is 90° is called the "critical angle, 6.", stated mathematically, when e: = 90°, 6, = 30 Record the critical angle for the water-to-air interface here:
Reflection and Refraction Critical angle for water-to-air, 6. = 87 Retum the angle of incidence to 0° and change the material in the top half to glass. Rotate the light source until the refracted ray is at 90° to the surface nomal. Record the critical angle for glass-to-air. Critical angle for glass-to-air, 6, =_89_ Repeat the process to find the critical angles for material Mystery A and Mystery B. Record the results here: There Critical angle for Mystery A, 6. = 87 Critical angle for Mystery B, 6, = 89 Collect the critical angle results of each of the materials and enter these into Table 5 below, then calculate the values for the third column in the Table 5. Table 5: Data for Activity 3. Material Critical Angle, e. sin 6. Refractive index, n Water 87 0.999 1.0014 Glass 89 0.991 1.5002 Mystery Material A 87 0.999 1.00 Mystery Material B 89 0.991 1.00 Q14. Complete the following statement. The index of refraction of the lower medium, which is air, is n = _1.00027 Q15. Fill in the blanks. At the critical angle, the transmitted light makes an angle of °, thus, sin 0:= Now use Snell's Law to calculate for the index of refraction for each of the materials and enter these values into the last column in Table 5. Refer to Table 4 to identify the mystery materials. Q16. Mystery If your answers for n are not consistent with your earlier results and experiments, find out where the discrepancy lies and re-do the experiment if necessary. A is _Mystery B is
Transcribed Image Text:Reflection and Refraction Critical angle for water-to-air, 6. = 87 Retum the angle of incidence to 0° and change the material in the top half to glass. Rotate the light source until the refracted ray is at 90° to the surface nomal. Record the critical angle for glass-to-air. Critical angle for glass-to-air, 6, =_89_ Repeat the process to find the critical angles for material Mystery A and Mystery B. Record the results here: There Critical angle for Mystery A, 6. = 87 Critical angle for Mystery B, 6, = 89 Collect the critical angle results of each of the materials and enter these into Table 5 below, then calculate the values for the third column in the Table 5. Table 5: Data for Activity 3. Material Critical Angle, e. sin 6. Refractive index, n Water 87 0.999 1.0014 Glass 89 0.991 1.5002 Mystery Material A 87 0.999 1.00 Mystery Material B 89 0.991 1.00 Q14. Complete the following statement. The index of refraction of the lower medium, which is air, is n = _1.00027 Q15. Fill in the blanks. At the critical angle, the transmitted light makes an angle of °, thus, sin 0:= Now use Snell's Law to calculate for the index of refraction for each of the materials and enter these values into the last column in Table 5. Refer to Table 4 to identify the mystery materials. Q16. Mystery If your answers for n are not consistent with your earlier results and experiments, find out where the discrepancy lies and re-do the experiment if necessary. A is _Mystery B is
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