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Table 3 - Resistivity of Different Materials Length of the wires: 0. 240 m Cross Sectional Caleulate Theoretical Diameter Voltage Current Resistance Percent Area Resistivity Resistivity (m) (V) (A) Error ( ) 0.001016 0.00575 1.09775 0.001016 0.2934 0.96121 0.001016 0.2200 0.95525

Table 3 - Resistivity of Different Materials Length of the wires: 0. 240 m Cross Sectional Caleulate Theoretical Diameter Voltage Current Resistance Percent Area Resistivity Resistivity (m) (V) (A) Error ( ) 0.001016 0.00575 1.09775 0.001016 0.2934 0.96121 0.001016 0.2200 0.95525

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Discussion: Ohm's Law describes the relationship between the resistance (R) of a wire, the voltage drop across it (V), and current through it (1): V = RI (1) Applying a known current to a wire and measuring the voltage across it will let you determine the resistance of the wire by solving equation 1: (2) The resistance of a particular element depends on its geometry, the resistivity and the temperature. Resistivity is the tendency of the material to behave as a resistor and is an inherent property of a material, in the same sense that density or thermal expansion are inherent properties. Materials with lower resistivity, like copper, are good conductors of electricity and widely used in cireuit components while those with larger resistivity, like rubber, are used as insulators. For a wire with length (L), cross-sectional area (A), and made from a material with resistivrity (p) the resistance (R) will be given by the following equation: R= ,L (3) In case that the geometry (length and cross sectional area) and the resistance of the wire is known, then is possible to caleulate the resistivity solving equation 3: RA (4) A wire can be consider as a long cylinder; then the cross sectional area would have a circular shape as shown in Figure 2. . Cross Sectional Area Length Figure 2 Then the cross sectional area of the wire can be caleulated using the equation of the area of a cirele: A = mr? (5) In this experiment, you will measure V and I to determine R for various lengths of wire. You will then make a graph of Resistance (Y-axis) versus length (X-axis). The plot will result in a straight line that has a slope equal to slope =, (6) From equation 6, it is possible to solre the resistivity in terms of the slope and the cross sectional area: p = slope + A (7) The manufacture values of the resistivrity corresponding to the wires used in the experiment are reported in Table 1. These values will be used as the theoretical when caleulating percent error. Table 1. Theoretical resistivity of different materials according to manufacturer. | Attracted to Magnet Dinmeter (m) No Material Color Resistivity (Qm) 7.0 x10* Brass Yellow 0.000508 0.000813 0.001016 0.001270 Copper Nicbrome No Dark Gray No Dark Gray 1.8 x10* 105 x10 79 x10 Red 0.001016 0.001016 Stainless Yes 0.001016 Steel
Transcribed Image Text:Discussion: Ohm's Law describes the relationship between the resistance (R) of a wire, the voltage drop across it (V), and current through it (1): V = RI (1) Applying a known current to a wire and measuring the voltage across it will let you determine the resistance of the wire by solving equation 1: (2) The resistance of a particular element depends on its geometry, the resistivity and the temperature. Resistivity is the tendency of the material to behave as a resistor and is an inherent property of a material, in the same sense that density or thermal expansion are inherent properties. Materials with lower resistivity, like copper, are good conductors of electricity and widely used in cireuit components while those with larger resistivity, like rubber, are used as insulators. For a wire with length (L), cross-sectional area (A), and made from a material with resistivrity (p) the resistance (R) will be given by the following equation: R= ,L (3) In case that the geometry (length and cross sectional area) and the resistance of the wire is known, then is possible to caleulate the resistivity solving equation 3: RA (4) A wire can be consider as a long cylinder; then the cross sectional area would have a circular shape as shown in Figure 2. . Cross Sectional Area Length Figure 2 Then the cross sectional area of the wire can be caleulated using the equation of the area of a cirele: A = mr? (5) In this experiment, you will measure V and I to determine R for various lengths of wire. You will then make a graph of Resistance (Y-axis) versus length (X-axis). The plot will result in a straight line that has a slope equal to slope =, (6) From equation 6, it is possible to solre the resistivity in terms of the slope and the cross sectional area: p = slope + A (7) The manufacture values of the resistivrity corresponding to the wires used in the experiment are reported in Table 1. These values will be used as the theoretical when caleulating percent error. Table 1. Theoretical resistivity of different materials according to manufacturer. | Attracted to Magnet Dinmeter (m) No Material Color Resistivity (Qm) 7.0 x10* Brass Yellow 0.000508 0.000813 0.001016 0.001270 Copper Nicbrome No Dark Gray No Dark Gray 1.8 x10* 105 x10 79 x10 Red 0.001016 0.001016 Stainless Yes 0.001016 Steel
Table 3 - Resistivity of Different Materials Length of the wires: 0.240 m Cross Sectional Calculate Theoretical Diameter Resistance Voltage (V) Сuтеnt Percent Area Resistivity Resistivity (m) (A) ( ) ( ) ( ) Error 0.001016 0.00575 1.09775 0.001016 0.2934 0.96121 0.001016 0.2200 0.95525
Transcribed Image Text:Table 3 - Resistivity of Different Materials Length of the wires: 0.240 m Cross Sectional Calculate Theoretical Diameter Resistance Voltage (V) Сuтеnt Percent Area Resistivity Resistivity (m) (A) ( ) ( ) ( ) Error 0.001016 0.00575 1.09775 0.001016 0.2934 0.96121 0.001016 0.2200 0.95525
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