How long Lis a tungsten wire if it has a diameter of 0.173 x 10-3 m and a resistance of 2.77 k2? The resistivity L = m of tungsten is 5.62 x 10-8 2-m.
How long Lis a tungsten wire if it has a diameter of 0.173 x 10-3 m and a resistance of 2.77 k2? The resistivity L = m of tungsten is 5.62 x 10-8 2-m.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
How long, \( L \), is a tungsten wire if it has a diameter of \( 0.173 \times 10^{-3} \) m and a resistance of \( 2.77 \, \text{k}\Omega \)? The resistivity of tungsten is \( 5.62 \times 10^{-8} \, \Omega \cdot \text{m} \).
**Equation to Solve:**
\[ L = \, \text{(to be completed by the user)} \]
**Units of Measurement:**
- \( L \): Length in meters (m)
**Additional Information:**
This problem is typically solved using the formula for the resistance of a wire:
\[ R = \rho \frac{L}{A} \]
Where:
- \( R \) is the resistance,
- \( \rho \) is the resistivity,
- \( L \) is the length,
- \( A \) is the cross-sectional area of the wire.
Use the formula to find the wire's length by rearranging it to solve for \( L \). Substitute known values once the cross-sectional area is calculated using the diameter of the wire.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F86752c1b-283e-4521-8dc6-ff7e4cb88ac7%2Fdef674c9-807c-4fab-bc59-c5f96c3ce4b1%2Fravfs5_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
How long, \( L \), is a tungsten wire if it has a diameter of \( 0.173 \times 10^{-3} \) m and a resistance of \( 2.77 \, \text{k}\Omega \)? The resistivity of tungsten is \( 5.62 \times 10^{-8} \, \Omega \cdot \text{m} \).
**Equation to Solve:**
\[ L = \, \text{(to be completed by the user)} \]
**Units of Measurement:**
- \( L \): Length in meters (m)
**Additional Information:**
This problem is typically solved using the formula for the resistance of a wire:
\[ R = \rho \frac{L}{A} \]
Where:
- \( R \) is the resistance,
- \( \rho \) is the resistivity,
- \( L \) is the length,
- \( A \) is the cross-sectional area of the wire.
Use the formula to find the wire's length by rearranging it to solve for \( L \). Substitute known values once the cross-sectional area is calculated using the diameter of the wire.
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