Table 1 Trial Angle [degrees] Hanging mass [kg] Moving mass [kg] Calculated acceleration (Equation 5) 1 3° 0.02746 kg 0.07231 kg 6.9686 m/s² 2 3° 0.02923 kg 0.07408 kg 6.8892 m/s² 3 3° 0.02924 kg 0.07409 kg 6.8887 m/s² Checking 3* Trials: 1. Trial 1 (6.9686 m/s²): • Difference from mean: 6.9686-6.9155 0.0531 ⚫ Since 0.0531 > 0.046, this value is outside 1 standard deviation. 2. Trial 2 (6.8892 m/s²): ⚫ Difference from mean: 16.8892-6.9155 0.0263 Since 0.0263 0.046, this value is within 1 standard deviation. 3. Trial 3 (6.8887 m/s²): Difference from mean: 6.8887-6.9155 -0.0268 Since 0.0268 <0.046, this value is within 1 standard deviation. Checking 3" Trials: 1. Trial 1 (6.9686 m/s²): Difference: 6.9686-6.9155) 0.0531 ⚫ Since 0.0531 > 0.0521, this is outside the margin of error. 2. Trial 2 (6.8892 m/s²): • Difference: 16.8892-6.9155 -0.0263 • Since 0.0263 <0.0521, this is within the margin of error. 3. Trial 3 (6.8887 m/s²): . Difference: 16.8887-6.9155 -0.0268 ⚫ Since 0.0268 0.0521, this is within the margin of error.
Table 1 Trial Angle [degrees] Hanging mass [kg] Moving mass [kg] Calculated acceleration (Equation 5) 1 3° 0.02746 kg 0.07231 kg 6.9686 m/s² 2 3° 0.02923 kg 0.07408 kg 6.8892 m/s² 3 3° 0.02924 kg 0.07409 kg 6.8887 m/s² Checking 3* Trials: 1. Trial 1 (6.9686 m/s²): • Difference from mean: 6.9686-6.9155 0.0531 ⚫ Since 0.0531 > 0.046, this value is outside 1 standard deviation. 2. Trial 2 (6.8892 m/s²): ⚫ Difference from mean: 16.8892-6.9155 0.0263 Since 0.0263 0.046, this value is within 1 standard deviation. 3. Trial 3 (6.8887 m/s²): Difference from mean: 6.8887-6.9155 -0.0268 Since 0.0268 <0.046, this value is within 1 standard deviation. Checking 3" Trials: 1. Trial 1 (6.9686 m/s²): Difference: 6.9686-6.9155) 0.0531 ⚫ Since 0.0531 > 0.0521, this is outside the margin of error. 2. Trial 2 (6.8892 m/s²): • Difference: 16.8892-6.9155 -0.0263 • Since 0.0263 <0.0521, this is within the margin of error. 3. Trial 3 (6.8887 m/s²): . Difference: 16.8887-6.9155 -0.0268 ⚫ Since 0.0268 0.0521, this is within the margin of error.
Chapter3: Energy And Conservation Laws
Section: Chapter Questions
Problem 3P: In Section 2.4, we computed the force needed to accelerate a 1,000-kg car from 0 to 27 m/s in 10 s....
Related questions
Question
Review the data in Data Table 1 and examine the standard deviations and 95% Margin of Error calculations from Analysis Questions 3 and 4 for the Acceleration of the 1st Based on this information, explain whether Newton’s Second Law of Motion, Equation 1, was verified for your 1st Angle.
Equation: SF=ma
Please help with explaining the information I collected from a lab and how it relates to the equation and Newton's Second Law. This will help with additional tables in the lab. Thanks!
![Table 1
Trial
Angle
[degrees]
Hanging
mass [kg]
Moving mass
[kg]
Calculated
acceleration
(Equation 5)
1
3°
0.02746 kg
0.07231 kg
6.9686 m/s²
2
3°
0.02923 kg
0.07408 kg
6.8892 m/s²
3
3°
0.02924 kg
0.07409 kg
6.8887 m/s²
Checking 3* Trials:
1. Trial 1 (6.9686 m/s²):
• Difference from mean:
6.9686-6.9155 0.0531
⚫ Since 0.0531 > 0.046, this value is outside 1 standard deviation.
2. Trial 2 (6.8892 m/s²):
⚫ Difference from mean:
16.8892-6.9155
0.0263
Since 0.0263 0.046, this value is within 1 standard deviation.
3. Trial 3 (6.8887 m/s²):
Difference from mean:
6.8887-6.9155 -0.0268
Since 0.0268 <0.046, this value is within 1 standard deviation.
Checking 3" Trials:
1. Trial 1 (6.9686 m/s²):
Difference:
6.9686-6.9155)
0.0531
⚫ Since 0.0531 > 0.0521, this is outside the margin of error.
2. Trial 2 (6.8892 m/s²):
• Difference:
16.8892-6.9155 -0.0263
• Since 0.0263 <0.0521, this is within the margin of error.
3. Trial 3 (6.8887 m/s²):
. Difference:
16.8887-6.9155 -0.0268
⚫ Since 0.0268 0.0521, this is within the margin of error.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc993bc3d-2ca5-48d7-9d6f-b44db78b61ed%2F011f79f9-1650-4915-9b6c-d25843c34e73%2F8c49kf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Table 1
Trial
Angle
[degrees]
Hanging
mass [kg]
Moving mass
[kg]
Calculated
acceleration
(Equation 5)
1
3°
0.02746 kg
0.07231 kg
6.9686 m/s²
2
3°
0.02923 kg
0.07408 kg
6.8892 m/s²
3
3°
0.02924 kg
0.07409 kg
6.8887 m/s²
Checking 3* Trials:
1. Trial 1 (6.9686 m/s²):
• Difference from mean:
6.9686-6.9155 0.0531
⚫ Since 0.0531 > 0.046, this value is outside 1 standard deviation.
2. Trial 2 (6.8892 m/s²):
⚫ Difference from mean:
16.8892-6.9155
0.0263
Since 0.0263 0.046, this value is within 1 standard deviation.
3. Trial 3 (6.8887 m/s²):
Difference from mean:
6.8887-6.9155 -0.0268
Since 0.0268 <0.046, this value is within 1 standard deviation.
Checking 3" Trials:
1. Trial 1 (6.9686 m/s²):
Difference:
6.9686-6.9155)
0.0531
⚫ Since 0.0531 > 0.0521, this is outside the margin of error.
2. Trial 2 (6.8892 m/s²):
• Difference:
16.8892-6.9155 -0.0263
• Since 0.0263 <0.0521, this is within the margin of error.
3. Trial 3 (6.8887 m/s²):
. Difference:
16.8887-6.9155 -0.0268
⚫ Since 0.0268 0.0521, this is within the margin of error.
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