(t_5) In a study of fast-food drive-through orders.  restaurant A had 294 accurate orders, 51 were wrong.  A) construct a 90% confidence interval estimate of the percentage of orders that are not accurate in decimal form.  ---- I did 51/345 which gave me 0.148. my confidence level is 1.90=.10/2=.05 my z-score is 1.645 then:  1.645 square root 0.148(1-.148)/345 then: 0.148 +-0.314.  this gave me 0.166 and 0.462  This is incorrect the answer is .0116 & 0.179   Can you help me figure out where I am going wrong.  This is an important chapter.  thank you

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2-Proportion Test

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