In a sample of 5 courses with no support course the average final of 200 students was 70%with a standard deviation of 10%. Calculate a 95% confidence interval for the mean ofstudents who did not take a support course. (Type numbers in Excel without percent sign)(68.61, 71.39)(68.61, 71.38)(68.60, 71.39)(69.96,70.04)O 5 is not larger than 40 so we cannot compute a confidence interval. A college has decided to add support courses to its statistics classes to assist students. Welook at the next semester to determine if the addition of the support courses assistedstudents. In a sample of 4 courses with support courses the average final grade of 160students was 78% with a standard deviation of 2%. Calculate a 95% confidence interval forthe population mean of students who took a support course. (Type numbers in Excelcalculator without percent sign)(77.69, 78.31)O (77.70, 78.30)(77.69,78.30)(77.68,78.31)4 is not larger than 40 so we cannot compute a confidence interval.

As per our guidelines we are suppose to answer only one question. Given,sample size(n)=200sample…

Answered: In a sample of 5 courses with no…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Suppose the mean height in inches of all 9th grade students at one high school is estimated. The population standard deviation is 3 inches. The heights of 6 randomly selected students are 71, 73, 69, 72, 71 and 64. x= Margin of error at 99%= confidence level = 99% confidence interval = [smaller value, larger value]=
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