In a sample of 5 courses with no support course the average final of 200 students was 70%with a standard deviation of 10%. Calculate a 95% confidence interval for the mean ofstudents who did not take a support course. (Type numbers in Excel without percent sign)(68.61, 71.39)(68.61, 71.38)(68.60, 71.39)(69.96,70.04)O 5 is not larger than 40 so we cannot compute a confidence interval. A college has decided to add support courses to its statistics classes to assist students. Welook at the next semester to determine if the addition of the support courses assistedstudents. In a sample of 4 courses with support courses the average final grade of 160students was 78% with a standard deviation of 2%. Calculate a 95% confidence interval forthe population mean of students who took a support course. (Type numbers in Excelcalculator without percent sign)(77.69, 78.31)O (77.70, 78.30)(77.69,78.30)(77.68,78.31)4 is not larger than 40 so we cannot compute a confidence interval.

As per our guidelines we are suppose to answer only one question. Given,sample size(n)=200sample…

Answered: In a sample of 5 courses with no…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The researcher recorded the amount of time each bird spent in the plain chamber during a 60-minute session. Suppose the study produced a mean of M = 44.62 minutes on the plain chamber with SS = 206 for a sample of n = 10 birds. Construct the 99% confidence interval to estimate the mean amount of time spent on the plain side for the population of birds. Please type only the lower interval with three decimal places. For example if CI= ( 10.25, 15), then type 10.25 as your answer.
A random sample of 120 rhesus monkeys found that the number of rhesus monkeys that live in a captive breeding facility is 77. Construct a 90% confidence interval for the true proportion of rhesus monkeys that live in a captive breeding facility.
Suppose the mean height in inches of all 9th grade students at one high school is estimated. The population standard deviation is 3 inches. The heights of 6 randomly selected students are 71, 73, 69, 72, 71 and 64. x= Margin of error at 99%= confidence level = 99% confidence interval = [smaller value, larger value]=
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Suppose the mean height in inches of all 9th grade students at one high school is estimated. The population standard deviation is 3 inches. The heights of 7 randomly selected students are 72, 61, 74, 68, 64, 66 and 64. x¯ = Margin of error at 95% confidence level = 95% confidence interval = [ , ]
A researcher investigated whether the temperature of milk, x, can be used to predict the milk's pH content, y. She predicted the pH level of a glass of milk with a temperature of 8.45 degrees to be ŷ= 6.795 a)A 95% confidence interval for the mean pH of all milk with temperature 8.45 degrees is calculated to be (6.76, 6.83). Which of the following is the correct interpretation of this confidence interval? -The mean pH level for all glasses of milk having a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -The pH level for one glass of milk with a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -There is a probability of 0.95 that the mean pH level for this glass of milk with temperature 8.45 degrees is between 6.76 and 6.83. -95% of all glasses of milk with a temperature of 8.45 degrees have a pH level between 6.76 and 6.83. b)Suppose we have a glass of milk whose temperature is 8.45 degrees. We…
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