t-testTests the claim that 4i # µ2. Assume the samples are normally distributed, random and independent.of = o}81 = 0.75 ; s2 = 0.74ž1 = 46.83 ; zz = 47.02T1 = 12 ; n2 = 12Degrees ofFreedomStandard Errort-Test Statistic(n1 – 1) · sỉ + (n2 – 1) · s(ž1 – 72) – (µ1 – 42)n1 + n2ni + n2 – 272a. Calculate the Standard Error s,-i(use 3 decimals)b. Calculate the t-test statistic using the standard error from part a. t=(use 2 decimal places)c. What are the degrees of freedom? df =d. At a = 0.02 , Use the distribution table to find the critical values for the rejection regionte = +(use 4 decimal places)

t-test Tests the claim that µi # µ2. Assume the samples are normally distributed, random and independent. of = o} 81 = 0.75 ; s2 = 0.74 ž1 = 46.83; zz = 47.02 %3D %3D 721 = 12; n2 = = 12 Degrees of Freedom Standard Error t-Test Statistic (ni – 1) sỉ + (n2 – 1) · s (ž1 – 72) – (µi – µ2) n1 + ng – 2 ni + n2 – 2 n2 a. Calculate the Standard Error sz-ž (use 3 decimals) b. Calculate the t-test statistic using the standard error from part a. t = (use 2 decimal places) c. What are the degrees of freedom? df =

t-test Tests the claim that µi # µ2. Assume the samples are normally distributed, random and independent. of = o} 81 = 0.75 ; s2 = 0.74 ž1 = 46.83; zz = 47.02 %3D %3D 721 = 12; n2 = = 12 Degrees of Freedom Standard Error t-Test Statistic (ni – 1) sỉ + (n2 – 1) · s (ž1 – 72) – (µi – µ2) n1 + ng – 2 ni + n2 – 2 n2 a. Calculate the Standard Error sz-ž (use 3 decimals) b. Calculate the t-test statistic using the standard error from part a. t = (use 2 decimal places) c. What are the degrees of freedom? df =

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Consider regression model Y; = R + B,X; + B;X +U,with hypothetical data Ev = 50, Ex = 20. Eyx = 60, E = 30, Σχ-0.5 Σν-300 Find OLS estimates of B, and B and derive their variances. Calculate R'and interpret it Construct 95% confidence interval for B, and interpret it Q1: n= 25 i. ii. 111
Suppose you are testing the hypothesis that p > 0.62. You take a random sample of size n = 55. %3D The distribution needed for the test is: p' ~ N(0.62, ?) Round your answer to three decimals. Submit Question
Testing:H0: μ ≤ 26.5H1: μ > 26.5Your sample consists of 38 values, with a sample mean of 27.3. Suppose the population standard deviation is known to be 1.77.a) Calculate the value of the test statistic, rounded to 2 decimal places.z=b) At α=0.03, the rejection region is z < -1.88 or z > 1.88 z > 1.88 z < -1.88 z < -2.17 z > 2.17 z < -2.17 or z > 2.17 c) The decision is to Accept the null hypothesis Accept the alternative hypotheis Reject the null hypothesis Fail to reject the null hypothesis d) Suppose you mistakenly rejected the null hypothesis in this problem, what type of error is that? Type I Type II
What is R hat2 What is R hat2
please send complete handwritten solution for Q 1 I attached sample please do like sample questions
12:08 AT&T * 4 all 65% 3. RT = 22 and US = 18 VT = R UV = RS = ST = U II
7/8/22, 3:04 PM Area z TABLE V z 78877 99737 77238 23927 328797 97979 777738=283 09898 30003 99999 33233 38539 22 -3.4 -2.5 -0.5 0.0010 0.0013 .00 .01 .02 .06 .07 .08 .09 0.0007 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0002 0.0005 0.0005 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0003 0.0007 0.0006 0.0006 0.0006 0.0006 0.0006 0.0005 0.0005 0.0005 0.0009 0.0009 0.0009 0.0008 0.0008 0.0008 0.0008 0.0007 0.0007 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.0010 0.0010 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 0.0035 0.0034 0.0033 0.0032 0.0031 0.0030 0.0029 0.0028 0.0027 0.0026 0.0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 0.0036 0.0062 0.0060 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048 0.0082 0.0080 0.0078 0.0075 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094 0.0091 0.0089 0.0087 0.0084…
find P(X<6)
1 Maximum Likelihood Estimation 1.1 MLE Let X1,.., X, be a random sample from a distribution with pdf f(x; 0) = , for 0 < x < 0. Find the MLE of 0. 1-e-6
The round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 4.5 mm. Round values to 4 decimal places when possible. The probability that the jump's round off error is greater than 3.3 is P(x > 3.3) = P(x > 2.1 | x > 0.8) = Find the minimum for the upper quartile
#2 Find the probability for a normal variable
• The value of the test statistic is given by 1= • The p-value is the area under the curve to the right of the value of the test statistic. Student's t Distribution 0,4 + Step 1: Enter the number of degrees of freedom. 17 Step 2: Select one-tailed or two-tailed. 0.3+ O One-tailed O Two-tailed Step 3: Enter the test statistic. (Round to 3 decimal places.) 0.2+ 1.928 Step 4: Shade the area represented by the p-value. 0.1+ Step 5: Enter the p-value. (Round to 3 decimal places.) 0.0354 1= 1.928 (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by Ashley. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean number of cases directly generated ? by one previous case is greater than 2.6. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is…