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Give a solution to the system -Lis -10. 2 3 - 15 ¤(0) by solving the IVP with initial condition y(0). 9. 27 181 #(t) exp( t)cos( t) + exp( t) sin( t) Note: Use the eigenvalue that makes the argument to the trig functions positve for t > 0.

Give a solution to the system -Lis -10. 2 3 - 15 ¤(0) by solving the IVP with initial condition y(0). 9. 27 181 #(t) exp( t)cos( t) + exp( t) sin( t) Note: Use the eigenvalue that makes the argument to the trig functions positve for t > 0.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Give a solution to the system 2 3 - 15 - 10 x(0) by solving the IVP with initial condition y(0) 27 # (t) = exp t)cos( t) + exp( t) sin( t) Note: Use the eigenvalue that makes the argument to the trig functions positve for t > 0.
Transcribed Image Text:Give a solution to the system 2 3 - 15 - 10 x(0) by solving the IVP with initial condition y(0) 27 # (t) = exp t)cos( t) + exp( t) sin( t) Note: Use the eigenvalue that makes the argument to the trig functions positve for t > 0.
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Give a solution to the system 2 3 - 15 - 10. x(0) by solving the IVP with initial condition y(0) 27 -9 -9 (t) exp( -4 vt)cos( 3 vt) + exp( -4 vt) sin( 3 Vt) 27 13 Note: Use the eigenvalue that makes the argument to the trig functions positve for t > 0. -6- of #(t) 4t e 9. cos(3t) + 4t e sin(3t) 27 Part 2 of 3 Now take the derivative of the above solution and subtract – 4x (t) to obtain a second solution to the differential equation. 18 '(t) + 47(t) = exp( – 4t)cos(3t) + exp( – 4t)sin(3t)
Transcribed Image Text:Give a solution to the system 2 3 - 15 - 10. x(0) by solving the IVP with initial condition y(0) 27 -9 -9 (t) exp( -4 vt)cos( 3 vt) + exp( -4 vt) sin( 3 Vt) 27 13 Note: Use the eigenvalue that makes the argument to the trig functions positve for t > 0. -6- of #(t) 4t e 9. cos(3t) + 4t e sin(3t) 27 Part 2 of 3 Now take the derivative of the above solution and subtract – 4x (t) to obtain a second solution to the differential equation. 18 '(t) + 47(t) = exp( – 4t)cos(3t) + exp( – 4t)sin(3t)
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