Answered: T-30 = Cekt T = Cekt + 30 T(10) = 0°F:…

T-30 = Cekt T = Cekt + 30 T(10) = 0°F: 0 Ce¹0k + 30 (1) = T(20) = 15°F: = 15 Ce 20k + 30 (2) k = -0.06931 C = -60.00 T = 30 - 60.00e-0.06931 t B] T(0) =? T = 30-60e-0.06931 (0) T(0) = -30.00°F

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

explain how did it get the value of c and k

T-30 = Cekt
T = Cekt + 30
T(10) = 0°F:
0 Ce¹0k + 30 (1)
=
T(20) = 15°F:
15 Ce 20k + 30 (2)
=
k = -0.06931
C = -60.00
T = 30 - 60.00e-0.06931 t
B] T(0) =?
T = 30-60e-0.06931 (0)
T(0) = -30.00°F

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