(t² + 2t) dx = 2x + 8, x(1) = 1 dt

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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a.) identify the technique of integration most appropriate b.) solve
### Differential Equation with Initial Condition

The given differential equation is:

\[ (t^2 + 2t) \frac{dx}{dt} = 2x + 8, \quad x(1) = 1 \]

**Explanation:**

1. **Equation:** \( (t^2 + 2t) \frac{dx}{dt} = 2x + 8 \)
   - \(t^2 + 2t\): The coefficient of the derivative \(\frac{dx}{dt}\)
   - \(\frac{dx}{dt}\): The derivative of \(x\) with respect to \(t\)
   - \(2x + 8\): The right-hand side of the differential equation

2. **Initial Condition:** \( x(1) = 1 \)
   - This specifies that when \(t\) is 1, the value of \(x\) is 1.

### Further Steps:

1. **Simplify the Differential Equation:**
   - Consider simplifying the equation by dividing both sides by \(t^2 + 2t\) if it's not zero.

2. **Solve the Differential Equation:**
   - Use appropriate methods (such as separation of variables or integrating factor) to solve for \(x\).

3. **Apply the Initial Condition:**
   - Use \( x(1) = 1 \) to find the specific solution to the equation.

### Educational Objective:

This example introduces the concept of solving a first-order linear differential equation with an initial condition, providing a step-by-step approach to finding the specific solution.
Transcribed Image Text:### Differential Equation with Initial Condition The given differential equation is: \[ (t^2 + 2t) \frac{dx}{dt} = 2x + 8, \quad x(1) = 1 \] **Explanation:** 1. **Equation:** \( (t^2 + 2t) \frac{dx}{dt} = 2x + 8 \) - \(t^2 + 2t\): The coefficient of the derivative \(\frac{dx}{dt}\) - \(\frac{dx}{dt}\): The derivative of \(x\) with respect to \(t\) - \(2x + 8\): The right-hand side of the differential equation 2. **Initial Condition:** \( x(1) = 1 \) - This specifies that when \(t\) is 1, the value of \(x\) is 1. ### Further Steps: 1. **Simplify the Differential Equation:** - Consider simplifying the equation by dividing both sides by \(t^2 + 2t\) if it's not zero. 2. **Solve the Differential Equation:** - Use appropriate methods (such as separation of variables or integrating factor) to solve for \(x\). 3. **Apply the Initial Condition:** - Use \( x(1) = 1 \) to find the specific solution to the equation. ### Educational Objective: This example introduces the concept of solving a first-order linear differential equation with an initial condition, providing a step-by-step approach to finding the specific solution.
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