Q2)Researchers at a paint manufacturer are trying to develop a new type of gloss paint with a shorterdrying time than the current product. In order to test whether the drying time has been reduced,the researchers paint a square metre of each of the new and old paints on each of 10 differentsurfaces. The time, in hours, that each square metre takes to dry is recorded in the table below:Surface12345 67 8 910Old paint17.1 17.3 16.9 17.4 17.5 17.3 16.6 17.5 18.0 17.6New paint16.6 17.2 17.0 17.1 17.6 16.5 16.9 17.3 17.3 16.9(a) Test, at the 0.05 level of significance, whether there is any reduction in the mean drying time.(b) State the assumption required to carry out the test in (a).(c) Find the p-value of the test in (a).(?? Marks)

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Answered: Q2) Researchers at a paint manufacturer…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The quality control engineer at Palmer Industries is interested in estimating the tensile strength of steel wire based on its outside diameter and the amount of molybdenum in the steel. As an experiment, she selected 25 pieces of wire, measured the outside diameters, and determined the molybdenum content. Then she measured the tensile strength of each piece. The results of the first four are recorded in the table. Tensile Strength Outside Diameter Amount of Molybdenum Place (PSI ) Y (mm) X1 (Units) X2 A 11 0.3 6 B 9 0.2 5 C 16 0.4 8 D 12 0.3 7 Using a statistical software package, the QC engineer determined the multiple regression equation to be Y’=-0.5+20X1+1X2. a) Based on the equation, what is the estimated tensile strength of a steel wire having an outside diameter of .35 mm and 6.4 units of molybdenum? b) Interpret the value of b1 in the equation.
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The owner of a moving company typically has his most experienced manager predict the total number of labor hours that will be required to complete an upcoming move. In an effort to provide a more accurate method, the owner has decided to use the number of cubic feet moved as the independent variable and has collected data for 20 moves in which the travel time was an insignificant portion of the hours worked. Use the data provided to complete parts (a) through (d) below. E Click the icon to view the data table. .... a. Construct a scatter plot. Choose the correct graph below. Data table O A. OB. С. Cubic Feet Moved Labor Hours 60- 900- 60- 616 31.50 719 33.75 263 13.75 455 20.50 0- 900 Cubic Feet 60 900 Cubic Feet 551 29.25 Hours 712 34.75 b. Assuming a linear relationship, use the least-squares method to determine the regression coefficients b, and b,. 412 18.75 296 14.50 bo = 384 21.00 b, = 451 22.50 603 26.75 (Round to three decimal places as needed.) 442 21.75 651 31.00 336 16.25…
You want to determine the effect of soap on bacterial colonies. In order to make sure that the environment does not affect your experiment, you divide 13 different petri dishes in half - one side is exposed to soap, the other is a control. You may use R but please show all the steps and codes involved. You measure the number of colonies that grow in each petri dish and come up with the following results: petri dish: 1 2 3 4 5 6 7 8 9 10 11 12 13soap: 10 5 7 10 19 11 13 17 19 8 11 10 16control: 20 17 11 17 26 18 21 25 24 17 17 17 21 Perform a complete hypothesis test to see if there is a difference in bacterial colonies between the soap and control dishes.
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Is there a difference in the amount of airborne bacteria between carpeted and uncarpeted rooms? In an experiment, seven rooms were carpeted and seven were left uncarpeted. The rooms were similar in size and function. After a suitable period, the concentration of bacteria in the air was measured (in units of bacteria per cubic foot) in all of these rooms. The data and summaries are provided: x¯ s Carpeted rooms 184 22.0 Uncarpeted rooms 170 16.9 A 95% confidence interval for the difference in mean bacterial concentration in the air of carpeted rooms versus uncarpeted rooms (using the conservative value for the degrees of freedom) is: Select one: −11.7 to 39.7. −16.66 to 34.66. −7.47 to 31.47. −18.89 to 42.89.
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