system by back substitution. −2x −4y −z −3w = −1 y +6z +2w = 8 z +w = 2 −4w = −12 The solution set is , , , . (Type an integer or a simplified fraction.) Enter your answer in
system by back substitution. −2x −4y −z −3w = −1 y +6z +2w = 8 z +w = 2 −4w = −12 The solution set is , , , . (Type an integer or a simplified fraction.) Enter your answer in
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Solve the system by back substitution.
−2x
|
−4y
|
−z
|
−3w
|
=
|
−1
|
|
|
y
|
+6z
|
+2w
|
=
|
8
|
|
|
|
z
|
+w
|
=
|
2
|
|
|
|
|
−4w
|
=
|
−12
|
|
The solution set is
, , , .
(Type an integer or a simplified fraction.)Enter your answer in the edit fields and then click Check Answer.
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