Lydia and Claudia have the same number of charms in their collections. Lydia started with 6 charms and bought 3 more packs. Claudia started with 9 charms and bought 2 more packs. If each pack had x charms, which equation can be used to find x? A. x= (2 + 3) – (6 +9) B. x= 6+ 3 + 9 + 2 C. 6x+3 = 9x + 2 %3D D. 3x-2x = 6 + 9 %3D E. 3x+6 = 2x + 9
Lydia and Claudia have the same number of charms in their collections. Lydia started with 6 charms and bought 3 more packs. Claudia started with 9 charms and bought 2 more packs. If each pack had x charms, which equation can be used to find x? A. x= (2 + 3) – (6 +9) B. x= 6+ 3 + 9 + 2 C. 6x+3 = 9x + 2 %3D D. 3x-2x = 6 + 9 %3D E. 3x+6 = 2x + 9
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![25
Lydia and Claudia have the same number of
charms in their collections. Lydia started with
6 charms and bought 3 more packs. Claudia
started with 9 charms and bought 2 more packs.
If each pack had x charms, which equation can
be used to find x?
A. x= (2 + 3) (6 +9)
B. x= 6+ 3 + 9 + 2
C. 6x+3 = 9x + 2
D. 3x 2x = 6 + 9
E. 3x+6 = 2x + 9](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb128b847-c929-428f-a1ea-cc087a9b80ad%2F6ce3f81b-10d7-4251-9640-5fb0f92ffdc3%2Fewnouso_processed.jpeg&w=3840&q=75)
Transcribed Image Text:25
Lydia and Claudia have the same number of
charms in their collections. Lydia started with
6 charms and bought 3 more packs. Claudia
started with 9 charms and bought 2 more packs.
If each pack had x charms, which equation can
be used to find x?
A. x= (2 + 3) (6 +9)
B. x= 6+ 3 + 9 + 2
C. 6x+3 = 9x + 2
D. 3x 2x = 6 + 9
E. 3x+6 = 2x + 9
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