SY A refrigeration system of 100TR operates on a single stage saturated cycle at an evaporating temperature of -36 C (saturation pressure = 0.8845 bar) and a condensing temperature of 30 C (saturation pressure 11.67 bar).The saturated Enthalpies at the exit of evaporator and condenser are 1414 kJ/kg and 341.8 kJ/kg respectively. The compression index y =1.304, and the compressor is an 8 cylinder, reciprocating type with a clearance ratio of 0.05 and speed of 1750 RPM. The stroke- to-bore ratio is 0.8. The refrigerant may be assumed as a perfect gas with molecular weight of (M= 17.03 kg/kmol). Find: a) Power input to the compressor. b) COP of refrigeration. e) Compressor dimensions (diameter and stroke length).

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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SY A refrigeration system of 100TR operates on a single stage saturated cycle at an
evaporating temperature of -36 C (saturation pressure = 0.8845 bar) and a
condensing temperature of 30'C (saturation pressure 11.67 bar).The saturated
Enthalpies at the exit of evaporator and condenser are 1414 k.J/kg and 341.8 kJ/kg
respectively. The compression index y =1.304, and the compressor is an 8 cylinder,
reciprocating type with a clearance ratio of 0.05 and speed of 1750 RPM. The stroke-
to-bore ratio is 0.8. The refrigerant may be assumed as a perfect gas with molecular
weight of (M= 17.03 kg/kmol). Find:
a) Power input to the compressor.
b) COP of refrigeration.
e) Compressor dimensions (diameter and stroke length).
Transcribed Image Text:SY A refrigeration system of 100TR operates on a single stage saturated cycle at an evaporating temperature of -36 C (saturation pressure = 0.8845 bar) and a condensing temperature of 30'C (saturation pressure 11.67 bar).The saturated Enthalpies at the exit of evaporator and condenser are 1414 k.J/kg and 341.8 kJ/kg respectively. The compression index y =1.304, and the compressor is an 8 cylinder, reciprocating type with a clearance ratio of 0.05 and speed of 1750 RPM. The stroke- to-bore ratio is 0.8. The refrigerant may be assumed as a perfect gas with molecular weight of (M= 17.03 kg/kmol). Find: a) Power input to the compressor. b) COP of refrigeration. e) Compressor dimensions (diameter and stroke length).
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