Surgical complications: A medical researcher wants to construct an 80% confidence interval for the proportion of knee replacement surgeries that result incomplications.Part 1 of 2(a) An article in a medical journal suggested that approximately 9% of such operations result in complications. Using this estimate, what sample size isneeded so that the confidence interval will have a margin of error of 0.03?A sample of 150 operations is needed to obtain an 80% confidence interval with a margin of error of 0.03 using the estimate 0.09 for p.Part: 1 / 2Part 2 of 2(b) Estimate the sample size needed if no estimate of p is available.A sample ofoperations is needed to obtain an 80% confidence interval with a margin of error of 0.03 when noestimate of p is available.

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Answered: Surgical complications: A medical…

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter4: Equations Of Linear Functions

Section: Chapter Questions

Problem 8SGR

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What is an experiment?
We plan to sample parents in order to construct a 99% confidence interval for the proportion who believe that physical education has a positive effect on academic performance. Estimate the sample size needed so that a 99% confidence interval will have a margin of error of 0.025.
According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the proportion of California residents who reported insufficient rest or sleep during each of the preceding 30 days is 8.0%, while this percent is 8.8% for Oregon residents. These data are based on simple random samples of 11,545 California and 4,691 Oregon residents. Suppose we want to calculate a 99% confidence interval for the difference between the proportions of Californians and Oregonians who are sleepdeprived. 1. State the critical value for the interval (3 decimal places): 2. State the difference between the sample proportions, POregon-PCalifornia (3 decimal places): 3. State the standard error of the difference between the proportions (3 decimal places): 4. State the confidence interval being sure to use proper notation (3 decimal places each):
You are reading an article detailing a study designed to compare the average body massindex among hypertensive individuals (persons with high blood pressure) tonormotensive individuals. The study was conducted using participants in a health planoffered by a large insurance carrier. 200 randomly selected hypertensive participantswere compared to 200 randomly selected normotensive participants. The study reports a95% confidence interval (CI) for the mean difference in BMI between hypertensives andnormotensives. The 95% CI is (0.15 kg/m2, 2.43 kg/m2). However, no p-value isreported for testing the null hypothesis of no mean difference in BMI between the twogroups (a mean difference of 0 kg/mg2) versus the alternative of a non-zero meandifference. Luckily, you have taken this course, so you are able to determine:a. the p-value is < .05b. the p-value is > .05c. the p-value is exactly .05.d. the p-value is exactly .009e. None of the above.
We plan to sample students to construct a 98% confidence interval for the proportion who uses Yelp as online directory for discovering dining restaurants. Estimate the sample size needed so that a 98% confidence interval will have a margin of error of 0.024.
Looking at a poll, 74% of California adults (374 out of 506 surveyed) believe that education is one of the top issues facing California. We want to construct a 90% confidence interval for the true proportion of California adults who believe that education is one of the top issues facing California. How do I find the error bound? (note:I must round answer to three decimal places)
An online site presented this question, "Would the recent norovirus outbreak deter you from taking a cruise?" Among the 34,006 people who responded, 65% answered "yes." Use the sample data to construct a 90% confidence interval estimate for the proportion of the population of all people who would respond "yes" to that question. Does the confidence interval provide a good estimate of the population proportion?

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