Surgical complications: A medical researcher wants to construct an 80% confidence interval for the proportion of knee replacement surgeries that result incomplications.Part 1 of 2(a) An article in a medical journal suggested that approximately 9% of such operations result in complications. Using this estimate, what sample size isneeded so that the confidence interval will have a margin of error of 0.03?A sample of 150 operations is needed to obtain an 80% confidence interval with a margin of error of 0.03 using the estimate 0.09 for p.Part: 1 / 2Part 2 of 2(b) Estimate the sample size needed if no estimate of p is available.A sample ofoperations is needed to obtain an 80% confidence interval with a margin of error of 0.03 when noestimate of p is available.

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Answered: Surgical complications: A medical…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You developed a simulation for the Walton bookstore example for company profits. According to your simulation results the mean profit is $204.13 with a standard deviation of $328.04. You want to build a 95% confidence interval of length $25 (i.e. the difference between the upper and lower limit of the confidence interval will be $25). Assume that the multiple for a 95% confidence level is 2. Compute the minimum number of replications required to build the desired confidence interval. a. 2000 to 3000 b.1000 to 2000 c. More than 4000 d. 3000 to 4000 e. Less than 1000
Provide an explanation as to why it would be very unlikely that a different sample of size n=30 would produce the same confidence interval.
Suppose a 90 percent confidence interval to estimate a population proportion was calculated from a sample proportion of 18 percent and a margin of error of 4 percent. What is the width of the confidence interval?
Suppose we know that a confidence interval for a population proportion is (0.105,0.355), with a sample proportion of p̂=0.23. What is the margin of error?
Estimate the sample size needed if no estimate of p is available. PART B
You may need to use the appropriate appendix table or technology to answer this question. The following results come from two independent random samples taken of two populations. Sample 1 Sample 2 n1 = 60 n2 = 25 x1 = 13.6 x2 = 11.6 ?1 = 2.4 ?2 = 3 (a) What is the point estimate of the difference between the two population means? (Use x1 − x2.) (b) Provide a 90% confidence interval for the difference between the two population means. (Use x1 − x2. Round your answers to two decimal places.) to (c) Provide a 95% confidence interval for the difference between the two population means. (Use x1 − x2. Round your answers to two decimal places.) to
Part 1 and 2
Part 1 of 3: A car company takes a random sample of 40 cars and finds a mean mileage of 28.1 mpg. If the company knows the population standard deviation is 4.7 mpg, Find the 3-decimal small value of the 92% confidence interval. Part 2 of 3: Find the 3-decimal large value of the 92% confidence interval. Part 3 of 3: Find the 3-decimal margin of error
A. True or False? A researcher compares the BMI of two populations of individuals from different socioeconomic backgrounds and finds that the proportion of individuals considered obese and from a poor background is .37 (n = 112), and the proportion of individuals considered obese and from an affluent background is .27 (n = 87); a 95% confidence interval for the risk difference for obesity among members of the poor population compared to the affluent population is (-0.03, 0.23). B. Why is it true or false?
You may need to use the appropriate appendix table or technology to answer this question. A survey conducted by the American Automobile Association showed that a family of four spends an average of $215.60 per day while on vacation. Suppose a sample of 64 families of four vacationing at Niagara Falls resulted in a sample mean of $252.45 per day and a sample standard deviation of $72.50. (a) Develop a 95% confidence interval estimate of the mean amount spent per day in dollars by a family of four visiting Niagara Falls. (Round your answers to the nearest cent.) $ ___ to $ ___ (b) Based on the confidence interval from part (a), does it appear that the population mean amount spent per day by families visiting Niagara Falls differs from the mean reported by the American Automobile Association? Explain. (1) No. The overall average daily vacation expenditure of $215.60 per day is between the upper and lower limits of the confidence interval for the population mean at Niagara Falls.…
You want to design a study to estimate the proportion of students on your campus who agree with the statement “The student government is an effective organization for expressing the needs of students to the administration.” You will use a 90% confidence interval and you would like the margin of error to be 0.05 or less. In previous years, it has been noted that the 32% of the campus agree with the statement. The minimum sample size required is approximately (A) 22 (B) 1795 (C) 335 (D) 236 If you feel the answer is none of the choices given, submit no answer to the question.
In a two-proportion study, we have p1= 0.682 with a sample size of 49 and p2= 0.612 with a sample size of 54. What would be the standard error in computing a confidence interval for the difference of proportions?

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