Surgical complications: A medical researcher wants to construct a 99.8% confidence interval for the proportion of knee replacement surgeries that result in complications. Part: 0 / 2 Part 1 of 2 (a) An article in a medical journal suggested that approximately 5% of such operations result in complications. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.05? A sample of operations is needed to obtain a 99.8% confidence interval with a margin of error of 0.05 using the estimate 0.05 for p. X S
Q: Sample 1 Sample 2 "1 = 400 "2 n2 = 300 P₁ = 0.53 P₂ = 0.35 What is the point estimate of the…
A: For sample 1:sample size (n1)= 400sample proportion p1^ = 0.53For sample 2:sample size (n2)=…
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Q: Surgical complications: A medical researcher wants to construct a 90% confidence interval for the…
A: From the provided information,Confidence level = 90%Proportion (p) = 0.10Margin of error (E) = 0.04
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A: Given that x̄ = 13.3 , s = 9.8 , n = 53
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A: (a)
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A: x1=59, n1=98=59+39x2=29, n2=84=29+55
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A: Let P₁ denote the proportion of patients who had the old procedure needing pain medication.
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A: Sample mean = 628Standard deviation = 50
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A: Given: Sample proportion p^=52%=0.52 Sample size (n) = 400
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Q: A study of 420,015 cell phone users found that 139 of them developed cancer of the brain or nervous…
A: a) From the provided information, Sample size (n) = 420,015 139 of them developed cancer of the…
Q: Pain after surgery: In a random sample of 51 patients undergoing a standard surgical procedure, 22…
A: Givenn1=51x1=22p1^=x1n1=2251=0.4314n2=88x2=16p2^=x2n2=1688=0.1818Confidence interval = 99.5%
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A: here for sample1 and sample2 data are respectively n1 = 31+47 = 78 n2 = 92 x1 = 31 x2 = 45…
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A: We have given that, X1 = 15, n1 = 42 and X2 = 11, n2 = 90 Then, We will find the 95% confidence…
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A: n1 = 400 n2 = 300 p1 = 0.49 p2 = 0.32
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Q: A study of 420,082 cell phone users found that 136 of them developed cancer of the brain or nervous…
A: Given, p^=136420082=0.00032 Rate of cancer for the people who did not use cell phones = 0.0415%
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- A 99% confidence interval guarantees that the true population mean value lies within this confidence range around the measured mean True FalseA computer store near campus is stocking its shelves and wants to know the relative proportions of students who use PCs vs Macs. A random sample of 60 students is surveyed, and each student is asked whether they use a PC or Mac more often. 55% select ”PC.” (a) What is the population and what is the sample in this study? (b) Calculate a 95% confidence interval for the proportion of UCI students that are PC users. (c) Provide an interpretation of this confidence interval in the context of this problem. (d) The confidence interval is pretty wide and leaves a lot of uncertainty over the proportion of UCIundergarduates who use PCs. With the goal to estimate a narrower 95% confidence interval, what is a simple change to this study that you could suggest for the next time that a similar survey is conducted?A medical researcher wants to construct a 95% confidence interval for the proportion of knee replacement surgeries that result in complications. A journal article suggested that approximately 6% of such operations result in complications. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.05?
- Pain after surgery: In a random sample of 54 patients undergoing a standard surgical procedure, 15 required medication for postoperative pain. In a random sample of 94 patients undergoing a new procedure, only 16 required pain medication. Part: 0/ 2 Part 1 of 2 (a) Construct a 99% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. Let p, denote the proportion of patients who had the old procedure needing pain medication. OL Use tables to find the critical value and round the answer to at least three decimal places. A 99% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures isSurgical complications: A medical researcher wants to construct a 90% confidence interval for the proportion of knee replacement surgeries that result in complications. En Part: 0 / 2 Part 1 of 2 (a) An article in a medical journal suggested that approximately 18% of such operations result in complications. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.06? A sample of 111 operations is needed to obtain a 90% confidence interval with a margin of error of 0.06 using the estimate 0.18 for p. Part: 1/ 2 Part 2 of 2 (b) Estimate the sample size needed if no estimate of p is available. A sample of operations is needed to obtain a 90% confidence interval with a margin of error of 0.06 when no estimate of p is available. Microsoft Excel NOV 20 MacBook Air DD 80 888 F10 FB F9 F5 F6 F7 F4 F3Question:Boys and girls: The National Health Statistics Reports reported that a sample of 311 one-year-old boys had a mean weight of 25.3 pounds with a standard deviation of 3.6 pounds. In addition, a sample of 287 one-year-old girls had a mean weight of 24.2 pounds with a standard deviation of 4.0 pounds. Part: 0 / 2 0 of 2 Parts Complete Part 1 of 2 Construct a 95 % confidence interval for the difference between the mean weights. Let μ1 denote the mean weight of one-year-old boys. Use tables to find the critical value and round the answers to at least one decimal place. A 95 % confidence interval for the difference between the mean weights isHip surgery: In a sample of 129 hip surgeries, the average surgery time was 138.1 minutes with a standard deviation of 23.3 minutes. A. Construct a 99% confidence interval for the mean surgery time for this procedure. Round the answer to one decimal place.A study of 420,031 cell phone users found that 136 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0316% for those not using cell phones. Complete parts (a) and (b). a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. %A. True or False? A researcher compares the BMI of two populations of individuals from different socioeconomic backgrounds and finds that the proportion of individuals considered obese and from a poor background is .37 (n = 112), and the proportion of individuals considered obese and from an affluent background is .27 (n = 87); a 95% confidence interval for the risk difference for obesity among members of the poor population compared to the affluent population is (-0.03, 0.23). B. Why is it true or false?WHen writing a null hypothesis for a two sample t test. Do you write U1 = U2 or U1 - U2 = 0? Or do both of them work?Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. 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