Suppose you want to prove that a ring homomorphism :R→S preserves nth powers of the ring, that is f(x^) = f(x)", by mathematical induction. The initial case is n=1,f(x)=f(x). The induction assumption is f(xk) = f(x)k What could be a valid first two steps in the induction step which lead to a valid complete proof and form a necessary part of the proof? The goal of the induction step is to prove that f (x*+1) = f(x)k+1 not part of the actual proof. You can use the fact that for all positive integers n,for all z in the ring zn+1 = z"z, and the fact forall z,w in R, f(zw)=f(z)f(w). @ f(xk+1)=f(x*+1) A = f(x)k+1 f(xk+1) = f(x*x) В

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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A
f(x*+1)=f(x*+1)
= f(x)k+1
O f(x*+1) = f(x* x)
= f(xk+1)
В
a f(xk+1)=f(x*x)
= f(xk)f(x)
C
D f(x)+f(x) = f(xk+1)
f(xk) = f(x*)
D
%3D
Transcribed Image Text:A f(x*+1)=f(x*+1) = f(x)k+1 O f(x*+1) = f(x* x) = f(xk+1) В a f(xk+1)=f(x*x) = f(xk)f(x) C D f(x)+f(x) = f(xk+1) f(xk) = f(x*) D %3D
Suppose you want to prove that a ring
homomorphism :R→S preserves nth powers of
the ring, that is f(x") = f(x)", by
mathematical induction. The initial case is
n=1,f(x)=f(x). The induction assumption is
f(xk) = f(x)k
What could be a valid first two steps in the induction
step which lead to a valid complete proof and form a
necessary part of the proof? The goal of the induction
step is to prove that f (x*+1) = f(x)k+1
but this is
not part of the actual proof. You can use the fact that
for all positive integers n,for all z in the ring
zn+1 = z^z, and the fact forall z,w in R,
f(zw)=f(z)f(w).
f(xk+1) = f(xk+1)
%D
A
=f(x)k+1
B
f(xk+1) = f(xkx)
= f(xk+1)
%3D
B
Transcribed Image Text:Suppose you want to prove that a ring homomorphism :R→S preserves nth powers of the ring, that is f(x") = f(x)", by mathematical induction. The initial case is n=1,f(x)=f(x). The induction assumption is f(xk) = f(x)k What could be a valid first two steps in the induction step which lead to a valid complete proof and form a necessary part of the proof? The goal of the induction step is to prove that f (x*+1) = f(x)k+1 but this is not part of the actual proof. You can use the fact that for all positive integers n,for all z in the ring zn+1 = z^z, and the fact forall z,w in R, f(zw)=f(z)f(w). f(xk+1) = f(xk+1) %D A =f(x)k+1 B f(xk+1) = f(xkx) = f(xk+1) %3D B
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