Suppose you just received a shipment of twelve televisions. Three of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work? The probability that both televisions work is. (Round to three decimal places as needed.)

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### Probability of Selecting Working Televisions

#### Problem Statement
Suppose you just received a shipment of twelve televisions. Three of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work?

#### Solution Steps
1. **Calculate the probability both televisions work:**

   - Total televisions = 12
   - Defective televisions = 3
   - Working televisions = 12 - 3 = 9

   Probability both selected televisions are working:

   \[
   \text{Probability} = \frac{ \text{Combinations of selecting 2 working TVs} }{ \text{Combinations of selecting any 2 TVs} }
   \]

2. **Combinations Calculation:**

   - Combinations of selecting 2 working TVs = \( \binom{9}{2} \)
   - Combinations of selecting any 2 TVs = \( \binom{12}{2} \)

3. **Result:**

   Insert the result in the provided box and round to three decimal places as needed.

#### Additional Explanation

- There is no graph or diagram in this text.
  
- The focus is on understanding the calculation of combinations to determine the probability of selecting two working televisions from a mixed set.
Transcribed Image Text:### Probability of Selecting Working Televisions #### Problem Statement Suppose you just received a shipment of twelve televisions. Three of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work? #### Solution Steps 1. **Calculate the probability both televisions work:** - Total televisions = 12 - Defective televisions = 3 - Working televisions = 12 - 3 = 9 Probability both selected televisions are working: \[ \text{Probability} = \frac{ \text{Combinations of selecting 2 working TVs} }{ \text{Combinations of selecting any 2 TVs} } \] 2. **Combinations Calculation:** - Combinations of selecting 2 working TVs = \( \binom{9}{2} \) - Combinations of selecting any 2 TVs = \( \binom{12}{2} \) 3. **Result:** Insert the result in the provided box and round to three decimal places as needed. #### Additional Explanation - There is no graph or diagram in this text. - The focus is on understanding the calculation of combinations to determine the probability of selecting two working televisions from a mixed set.
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